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saw5 [17]
3 years ago
8

Can someone plz help me with this ​

Chemistry
1 answer:
lara31 [8.8K]3 years ago
7 0

A would be states of matter

B would be density

C would be Liquid

J is oxidation

H would be acid

D would be gas

I would be base

thats all i remember

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Which of the following is an example of a synthesis reaction?
Setler79 [48]
A, because a synthesis reaction is A+B—> AB

B is a decomposition AB—> A+B (opposite of synthesis)
C is acids and base acid 1 + base 1 —> acid 2 + base 2
D is double displacement AB+CD —> AD+CB
8 0
3 years ago
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0.158 g of a mystery molecule is placed into a bomb calorimeter that has a heat capacity of 1650 J/C. After the sample is combus
Lunna [17]

<u>Answer:</u> The molar mass of the mystery element is 111.27 g/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 1650 J/°C

\Delta T = change in temperature = 2.54^oC

Putting values in above equation, we get:

q=1650J/^oC\times 2.54^oC=4191kJ

Heat absorbed by the calorimeter will be equal to the heat released by the reaction.

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles of the mystery molecule, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat released = -4191 J

n = number of moles = ? moles

\Delta H_{rxn} = enthalpy change of the reaction = -2960 kJ/mol = -2960000 J/mol    (Conversion factor = 1 kJ = 1000 J)

Putting values in above equation, we get:

-2960000=\frac{-4191J}{n}\\\\n=\frac{-4191}{-2960000}=0.00142mol

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of mystery molecule = 0.158 g

Moles of mystery molecule = 0.00142 mol

Putting values in above equation, we get:

0.00142mol=\frac{0.158g}{\text{Molar mass of mystery molecule}}\\\\\text{Molar mass of mystery molecule}=\frac{0.158}{0.00142}=111.27g/mol

Hence, the molar mass of the mystery element is 111.27 g/mol

8 0
3 years ago
Nitrogen (N) and hydrogen (H) react with each other to produce ammonia (NH3). This reaction is shown in an equation as N2 + 3H2
Anika [276]
There are 2 Nitrogen atoms (or parts) of Nitrogen on the left side of the equation, and 2 Hydrogen, and only one Nitrogen but three Hydrogen on the other side. Where did the extra Nitrogen go? Where did that Hydrogen come from? The answer is Stoichiometry. 
N2 + H2 --> NH3 has to be balanced, so we add coefficients to the reactants and products, which indicate in what ratio they are consumed in the reaction. They effectively multiply the subscripts on the elements.
To balance Nitrogen, we have to add a 2 to the front of NH3, so we get 2NH3. Nitrogen is balanced, but Hydrogen isn't. There are now 6 Hydrogen being produced by the reaction, so we can add a 3 to the products side, making 3H2.
Now we have N2 + 3H2 --> 2NH3, and everything is balanced.
The ratio is 2:6, or 1:3
3 0
4 years ago
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Identify the power of ten that defines each of these prefixes. Input your answers as 10 x where x is the power of ten. nano- ___
Gemiola [76]

<u>Answer:</u> The quantity of every prefix is written below as a power of ten.

<u>Explanation:</u>

In the metric system of measurement, the name of multiples and subdivision of any unit is done by combining the name of the unit with the prefixes.

<u>For Example:</u> deka, hecto and kilo means 10, 100 and 1000 respectively. Deci, centi and milli means one-tenth, one-hundredth, and one-thousandth respectively.

The quantity of these prefixes are written as the power of 10.

For the given prefixes:

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<u>Kilo:</u>  The quantity will be 10^3

<u>Centi:</u>  The quantity will be 10^{-2}

<u>Micro:</u>  The quantity will be 10^{-6}

<u>Milli:</u>  The quantity will be 10^{-3}

<u>Mega:</u>  The quantity will be 10^6

Hence, the quantity of every prefix is written above as a power of ten.

7 0
4 years ago
why can't scientists collect temperature and volume data for an enclosed gas at temperatures near absolute zero.
sergeinik [125]
Absolute zero is measured in kelvin and kelvin is -324 degree celsius witch turns most elements turn solid
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