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saw5 [17]
3 years ago
8

Can someone plz help me with this ​

Chemistry
1 answer:
lara31 [8.8K]3 years ago
7 0

A would be states of matter

B would be density

C would be Liquid

J is oxidation

H would be acid

D would be gas

I would be base

thats all i remember

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A given mass of air has a volume of 8.00 L at 60.0°C. At constant pressure, the temperature is increased to 80.0°C. Calculate th
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Answer:

D. 6.00 L

Explanation:

What we have here is an example of Boyle's Law. The equation here is P₁ · V₁ = P₂ · V₂. We know all of the values except for V₂.

60(8) = 80V

<em>Multiply 60 by 8 to get 480.</em>

480 = 80V

<em>Divide both sides by 80.</em>

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The final volume for the gas is 6.00 L.

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2 years ago
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The awnser is D or the 4th one
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2 years ago
The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co
garri49 [273]

Answer:

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater (m_{sw}), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

m_{sw} = \rho_{sw}\cdot V_{sw}

Where:

\rho_{sw} - Density of seawater, measured in grams per liters.

V_{sw} - Volume of seawater, measured in liters.

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m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)

m_{sw} = 1.545\times 10^{24}\,g

The total mass of sodium chloride is determined by the following ratio:

r = \frac{m_{NaCl}}{m_{sw}}

m_{NaCl} = r\cdot m_{sw}

Given that m_{sw} = 1.545\times 10^{24}\,g and r = 0.035, the total mass of sodium chloride in all the seawater in the world is:

m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)

m_{NaCl} = 5.408\times 10^{22}\,g

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

8 0
3 years ago
To make a solution less concentrated, it is _____________________.
Crazy boy [7]

Answer:

Diluted

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Imagine having a sugar filled water (like a lot of them). This is a strong solution.

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