Answer:
Scientific notation is a way of expressing numbers that are too large or too small to be conveniently written in decimal form.The primary reason for converting numbers into scientific notation is to make calculations with unusually large or small numbers less cumbersome.
Step-by-step explanation:
Given:
PV = 13,440
i = 5.86% , compounded monthly
t = 4 years
13,440(0.0586/12))/(1-(1+0.0586/12)^-48= 15,109.44
15,109.44 + 156.60 = 15,266.04
15,266.04 - 13,440.00 = 1,826.04
<span>1,826.04/15,266.04 = 11.96 % Percentage total of Finance Charge of the total loa</span>
Answer:
Part 1) The expression for the perimeter is 
or 
Part 2) The perimeter when z = 15 ft. is 
Step-by-step explanation:
Part 1)
we have
Find the roots of the quadratic equation
Equate the equation to zero
Complete the square
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Factor the leading coefficient
Complete the square. Remember to balance the equation by adding the same constants to each side
Rewrite as perfect squares
-----> root with multiplicity 2
so
The area is equal to
![A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}](https://tex.z-dn.net/?f=A%3D625%28z-0.12%29%28z-0.12%29%3D%5B25%28z-0.12%29%5D%5B25%28z-0.12%29%5D%3D%2825z-3%29%5E%7B2%7D)
The length side of the square is 
therefore
The perimeter is equal to
Part 2) Find the perimeter when z = 15 ft.
we have
substitute the value of z
Step-by-step explanation:
From the question
Perimeter = 2L + 2W
L = 24 units
W = 11 units
Substitute the values into the above formula
That's
P = 2(24) + 2(11)
P = 48 + 22
P = 70 units
Therefore the perimeter of the rectangle cannot be 60 units since the values when substituted into the above formula will give us 70 units
Hope this helps you
The first stone will be 10-in wide
The last stone will be 10-in wide
The stones in the middle will be alternating between 5-in and 10-in stones, making a total of 15-in
Total width = 145-in
Width after placing first and last stones = 145 - 20 = 125-in
Number of 15-in patterns incorporated in 125-in:
125/15 = 8.33
Therefore, he will place 8 10-inch stones within and 9 5-inch stones within the patter.
The total 10-inch stones used = 8 + 2 = 10
