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natulia [17]
3 years ago
8

Dominic, Ralf and Peter have just eaten a HUGE Christmas meal. Dominic now weighs half as much as Ralph, and Peter weighs three

times as much as Dominic. Together they weigh 720 pounds. How much does Dominic weigh?
Mathematics
1 answer:
bulgar [2K]3 years ago
5 0
The question requires us to form an algebraic expression in order to calculate Dominic's weight, after telling us his weigh with respect to his peers and the sum of their weights. Let D represent Dominic's weight, R represent Ralph's weight and P represent Peter's weight. From the given information, we can form:
2D = R
3D = P
P + R + D = 720
Now, we substitute values into the last equation:
3D + 2D + D = 720
6D = 720
D = 120
Dominic's weight is 120 pounds
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Plz Answer this question fast, Thank You
AysviL [449]

Answer:

162

Step-by-step explanation:

20736 x 729 x 4/216 x 64 x27

Now go ahead and do the cancellations

20736/216 =96

729/27 =27

64/4 =16

so you end up getting 96 x 27 x1 /26

96/16 =6

so you get 27 x 6 =162

4 0
3 years ago
Read 2 more answers
Please Answer Quick 65 Points ! !
NeTakaya

The correct answers are:

  • The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true.
  • The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false.

Further explanation:

Given equations are:

2x-y = -5

x+3y = 22

We have to check whether the given statements are true or not. In order to find that we have to put the points in the equations

Putting the point in 2x-y = -5

2x - y = -5\\2(7) -19 = -5\\14-19 = -5\\-5 = -5

Putting the point in x+3y=22

7 + 3 (19) = 22\\7 + 57 = 22\\64 \neq 22

The point satisfies the first equation but doesn't satisfy the second. So,

1. The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true.

This statement is true as the point satisfies the first equation

2. The ordered pair (7, 19) is a solution to the second equation because it makes the second equation true.

This Statement is false.

3. The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false.

This statement is true.

4. The ordered pair (7, 19) is a solution to the system because it makes both equations true.

This statement is false as the ordered pair doesn't satisfy both equations.

Keywords: Solution of system of equations, linear equations

Learn more about solution of linear equations at:

  • brainly.com/question/13168205
  • brainly.com/question/1465430

#LearnwithBrainly

5 0
3 years ago
Terry evaluates 6 divided by 1/8 using multiplication expression
Volgvan

what is way two get to the south pole.

6 0
2 years ago
Find the y-intercept of the line. If needed use "/" for a fraction. b= <br><br>y=10+4x​
11111nata11111 [884]

Y-intercept(b)= 10

equation wasnt written in the correct order so b is 10

7 0
1 year ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
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