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4 years ago

A window washer does not want to change her position.

2 answers:

5 0

The answer should be C) Balanced because if she doesn't want to change spots/move, than she doesn't want to be in motion which means she wants to stay still and that would be balanced.

Scilla [17]4 years ago

4 0

Answer:

Explanation:

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Which statement is true about BF3, a nonpolar molecule? It has nonpolar bonds and a symmetrical structure. It has nonpolar bonds

konstantin123 [22]

I think the correct answer is the first option. It has nonpolar bonds and a symmetrical structure. The structure of a BF3 molecule shows a symmetrical trigonal geometry. The net dipole moment of the molecule is zero therefore it is polar.

6 0

3 years ago

Read 2 more answers

Type Calculations. Given the balanced equation: 2 Al + 3 H2SO4---> Al2(SO4)3 + 3 H2 Molar mass (g/mol): Al=26.98; H2SO4=98.08

Oxana [17]

Answer:

A. 1.88 mol H₂

B. 182 g Al₂(SO₄)₃

C. 54.8%

Explanation:

2 Al + 3 H₂SO₄ ⇒ Al₂(SO₄)₃ + 3 H₂

A. Convert grams of Al to moles. The molar mass is 26.98 g/mol.

(33.8 g)/(26.98 g/mol) = 1.253 mol Al

Use stoichiometry to convert moles of Al to moles of H₂. Looking at the equation, you can see that for every 2 mol of Al consumed, 3 moles of H₂ is produced. Use this relationship.

(1.253 mol Al) × (3 mol H₂)/(2 mol Al) = 1.879 mol H₂

You will produce 1.88 mol of H₂ gas.

B. Again, use stoichiometry. For every 3 moles of H₂SO₄ consumed, 1 mole of Al₂(SO₄)₃ is produced.

(1.60 mol H₂SO₄) × (1 mol Al₂(SO₄)₃/3 mol H₂SO₄) = 0.533 mol Al₂(SO₄)₃

Convert moles of Al₂(SO₄)₃ to grams. The molar mass is 342.15 g/mol.

(0.533 mol) × (342.15 g/mol) = 182.48 g Al₂(SO₄)₃

You will produce 182 g of Al₂(SO₄)₃.

C. Calculate percent yield by dividing the actual yield by the theoretical yield. Multiply by 100%.

(100.0/182.48) × 100% = 54.8%

The percent yield is 54.8%.

7 0

3 years ago

You perform a single extraction with 100 mL of chloroform to remove compound A from 100 mL of an aqueous solution. The partition

Mice21 [21]

Answer:

Percentage of mass of solute in aqueous phase is 28.57%.

Explanation:

$(q)_{aq}$ - Fraction of solute in aqueous phase.

$(q)_{aq}=\frac{V_{aqueous}}{DV_{organic}+V_{aqueous})}$

$V_{aqueous}$ = Used volume of aqueous solution

$V_{organic}$ = Used volume of organic solution

D = partition coefficient.

$(q)_{aq}=\frac{100ml}{(2.5\times100)+100\,ml}=0.2857$

Mass of solute in aqueous phase = $0.2857\times 5g=1.428g$

$Mass\,percentage = \frac{1.428}{5.0}\times 100=28.57$

Therefore, Percentage of mass of solute in aqueous phase is 28.57%.

5 0

3 years ago

Calculate each of the following quantities:<br> (b) Amount (mol) of O atoms in 8.18 g of Ba(NO₃)₂

postnew [5]

The number of moles of O atoms in 8.18 g of Ba(NO₃)₂ is 0.364 mol.

<h3>What is moles?</h3>

"The mole is a SI unit of measurement that is used to calculate the quantity of any substance." It is denoted by mol.

Given that the mass of Ba(NO₃)₂ is 8.18 g

n = m/M

n = moles = ? mol Ba(NO₃)₂

m = mass(g) = 8.18 gram(NO3)2

The molar mass of Ba(NO₃)₂ is 261. 35g/mol.

As given, the moles of oxygen atom in Ba(NO₃)₂ is 6.

So, the moles of oxygen in 8.18 gram will be

Putting the value in the formula:

0.0607 mol Mg(NO3)2 × 6 mol O atoms/mol Mg(NO3)2 = 0.364 mol O atoms to three significant figures.

Thus, the number of moles of O atoms is 0.364 mol.

To learn more about moles, refer to the link:

brainly.com/question/4220551

#SPJ4

8 0

2 years ago

Identify the term that matches each electrochemistry definition.

anygoal [31]

Answer: a. Cathode

b. Galvanic cell

c. Anode

d. Electrolytic cell

e. half reaction

Explanation:

Galvanic cell or Electrochemical cell is defined as a device which is used for the conversion of the chemical energy produced in a spontaneous redox reaction into the electrical energy.

Electrolytic cell is a device where electrical energy is used to drive a non spontaneous chemical reaction.

In the electrochemical cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode. Thus the electrons are produced at anode and travel towards cathode.

The balanced two-half reactions will be:

Oxidation half reaction : $M\rightarrow M^{n+}+ne^-$

Reduction half reaction : $N^{n+}+ne^-\rightarrow N$

Thus the overall reaction will be: $M+N^{n+}\rghtarrow M^{n+}+N$

4 0

3 years ago