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4 years ago

The pH of a solution is 5.0. To a 10 ml of this

Chemistry

1 answer:

mylen [45]4 years ago

8 0

Answer:

pH = 7

Explanation:

pH is defined as -log [H⁺]. In a solution of pH 5:

pH = -log [H⁺]

10^(-5) = [H⁺]

1x10⁻⁵M = [H⁺].

Then, this solution is diluted from 10mL to 1000mL (990mL of water + 10mL of the original solution). That means the solution is diluted:

1000mL / 10mL / 100 times.

If [H⁺] before dilution was 1x10⁻⁵M, after dilution will be:

1x10⁻⁵M / 100 = 1x10⁻⁷M

And pH:

pH = -log [H⁺]

pH = -log 1x10⁻⁷M

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A substance that produces hydroxide ions when placed in water is a(n) _____.

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Answer: A substance that produces hydroxide ions when placed in water is base.

Explanation:

Bases are the substance:

Which gives negatively charged hydroxide( $OH^-$ ) ions in aqueous solution.

Which have pH value ranging from 7 to 14.

$BOH(aq)\rightarrow B^+(aq)+OH^-(aq)$

Where as acid gives positively charged hydronium ion( $H^+$ ) in aqueous solution.

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3 years ago

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What kind of questions CANNOT be answered by chemistry?

Sergeu [11.5K]

Answer:

d. why matter exists

Explanation:

The kind of questions that chemistry CANNOT answer is "why matter exists".

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4 years ago

What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M

Fed [463]

36 ml of NaOh and 464 ml of HCOOH would be enough to form 500 ml of a buffer with the same pH as the buffer made with benzoic acid and NaOH.

What is benzoic acid found in?

Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 = 0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

$pH = pKa + log\frac{base}{acid}$

$4.2 + log\frac{0.05}{0.045} = 4.245$

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

$pH = pKa + log\frac{base}{acid}$

$4.245 = 3.75 + log\frac{base}{acid}$

$log\frac{base}{acid} = 0.5$

$\frac{base}{acid} = 3.162$

Now we must solve the equation above. This will be done using the following values

$\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L$

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

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2 years ago

The volume of a weather balloon is 200.0 L and its internal pressure is 1.17 atm when it is launched at 20 °C. The balloon rises

brilliants [131]

Answer:

2022 L

Explanation:

Ideal gas laws will work for gas in the balloon

The general gas law is for a gas at two arbitrary states 1 and 2 is given by

(P₁ V₁)/T₁ = (P₂ V₂)/T₂

P₁ = 1.17 atm

V₁ = 200.0 L

T₁ = 20°C = 293.15 K

P₂ = 63 mmHg = 0.0829 atm

V₂ = ?

T₂ = 210 K

(1.17 × 200)/293.15 = (0.0829 × V₂)/210

V₂ = (210 × 1.17 × 200)/(293.15 × 0.0829)

V₂ = 2022 L

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4 years ago