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Vitek1552 [10]
4 years ago
12

If you wanted to measure in irregular object's volume, which device would you use?

Chemistry
1 answer:
EleoNora [17]4 years ago
3 0

Answer:

a beaker

Explanation:

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A brick has a mass of 4.0 kg and the Earth has a mass of 6.0 × 1027 g. Use this information to answer the questions below. Be su
Vedmedyk [2.9K]

Answer:

a) 2.4\times 10^{24} kg is the mass of 1 mole of bricks.

b) 2.5\times 10^3 moles of bricks have a mass equal to the mass of the Earth.

Explanation:

a) Mass of brick = 4.0 kg

1 mole = N_A=6.022\times 10^{23} particles/ atoms/molecules

Mass of N_A bricks :

=6.022\times 10^{23}\times 4.0 kg=2.4088\times 10^{24} kg\approx 2.4\times 10^{24} kg

2.4\times 10^{24} kg is the mass of 1 mole of bricks.

b)

Mass of the Earth = M = 6.0\times 10^{27} kg

Mass of 1 mole of brick = m=2.4\times 10^{24} kg

Let the moles of brick with equal mass of the Earth be x.

m\times x=M

x=\frac{M}{m}=\frac{6.0\times 10^{27}kg}{2.4\times 10^{24} kg}=2.5\times 10^3

2.5\times 10^3 moles of bricks have a mass equal to the mass of the Earth.

7 0
3 years ago
What is the meaning of CPI?<br>​
LekaFEV [45]

Answer:

(CPI) Consumer Price Index

Explanation:

A consumer price index measures changes in the price level of a weighted average market basket of consumer goods and services purchased by households. A CPI is a statistical estimate constructed using the prices of a sample of representative items whose prices are collected periodically.

6 0
3 years ago
Displacement is the slope of a velocity vs. time graph<br><br> A. True<br><br> B. False
mezya [45]

Answer:

The given statement is false.

Explanation:

Displacement is a vector quantity which represent shortest distance form initial position to final position.

Velocity of an object is defined as ratio of displacement of object to that of the time taken by object to move from its initial position to final position.

In displacement vs time graph the slope of the graph represent the velocity. Whereas slope of velocity vs time graph gives acceleration.

6 0
3 years ago
A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed
AlekseyPX

(a) 4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 20.68N_2;

(b) 4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2;

(c) 23 900 kg air; (d) air:fuel = 10.2; (e) air:fuel = 12.2:1

(a) <em>Balanced equation including N_2 from air</em>  

The balanced equation <em>ignoring</em> N_2 from air is  

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2  

Moles of N_2 =55 mol O_2 × (3.76 mol N_2/1 mol O_2) = 206.8 mol N_2  

<em>Including</em> N_2 from air, the balanced equation is  

4C_11 H_7S + 55O_2 → 44CO_2 + 14H_2O + 4SO_2 + 206.8N_2  

(b) <em>Balanced equation for 120 % stoichiometric combustion</em>  

Moles of O_2 = 55 mol O_2 × 1.20 = 66.00 mol O_2  

Excess moles O_2 = (66.00 – 55) mol O_2 = 11.00 mol O_2  

Moles of N_2 = 66.00 mol O_2 × (3.76 mol N_2/1 mol O_2) = 248.2 mol N_2  

The balanced equation is

4C_11 H_7S + 66O_2 → 44CO_2 + 14H_2O + 4SO_2 + 248.2N_2 + 11O_2

(c) <em>Minimum mass of air</em>  

Moles of O_2 required = 1700 kg C_11 H_7S

× (1 kmol C_11 H_7S/185.24 kg C_11 H_7S) × (55 kmol O_2/4 kmol C_11 H_7S)

= 126.2 kmol O_2  

Mass of O_2 = 126.2 kmol O_2 × (32.00 kg O_2/1 kmol O_2) = 4038 kg O_2  

Mass of N_2 required = 126.2 kmol O_2 × (3.76 kmol N_2/1 kmol O_2)

× (28.01 kg N_2/1 kmol N_2) = 13 285 kg N_2  

Mass of air = Mass of N_2 + mass of O_2 = (4038 + 13 285) kg = 17 300 kg air  

(d) <em>Air:fuel mass ratio for 100 % combustion</em>  

Air:fuel = 17 300 kg/1700 kg = <em>10.2 :1 </em>

(e) <em>Air:fuel mass ratio for 120 % combustion </em>

Mass of air = 17 300 kg × 1.20 = 20 760 kg air  

Air:fuel = 20 760 kg/1700 kg = 12.2 :1  

6 0
3 years ago
How many atoms are in 3.5 moles of NaCl?
Ivenika [448]

Answer:

2.11  ×10²⁴ atoms

Explanation:

Given data:

Number of moles of NaCl = 3.5 mol

Number of atoms = ?

Solution:

It is known that 1 mole contain 6.022×10²³ atoms. The number 6.022×10²³ is called Avogadro number.

3.5 mol ×6.022×10²³ atoms / 1 mol

21.1 ×10²³ atoms

2.11  ×10²⁴ atoms

5 0
3 years ago
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