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WINSTONCH [101]
3 years ago
12

What is this graph showing?

Chemistry
1 answer:
stepladder [879]3 years ago
3 0

Explanation:

It's a distance-time graph showing the speed of an object

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Calculate the work (kJ) done during a reaction in which the internal volume expands from 18 L to 49 L against a vacuum (an outsi
IgorLugansk [536]

Answer:

b

Explanation:

b

4 0
3 years ago
200.0ml of a .800 M solution of sodium phosphate is reacted with excess lead acetate as shown below. How many grams of lead phos
Julli [10]

Answer:

The mass of the solid precipitate (HgSO₄) is 27.529 g

Explanation:

I did the test

4 0
3 years ago
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction
inessss [21]

Answer:

Explanation:

2 NH4I    + Pb(NO3)2   =  PbI2  + 2 NH4NO3

2 mol          1 mol

x ml             751 ml

0.550 M      0.380 M

0.380 mol/1000 ml  x 751 ml =  0.285 mol Pb(NO3)2

0.285 mol Pb(NO3)2 x 2 mol NH4I/1 mol  Pb(NO3)2=0.571 mol  NH4I  needed

0.571 mol  NH4I/0.550 mol/1000 ml=1038 ml

6 0
3 years ago
Predict (to 3 sig figs) the isochoric specific heat of gaseous SF6 (molar mass 146.06 g/mol) at 1200 K, assuming that at this te
bazaltina [42]

Explanation:

As it is known that SF_{6} molecule is a non-linear molecule. Therefore, its isochoric heat capacity will be as follows.

              C_{v} = \frac{3}{2}R + \frac{3}{2}R + (3 \times 7 - 6)R

                         = \frac{3}{2}R + \frac{3}{2}R + 15R

                         = 18 R

Also,    C_{V} = M \times C_{v}

where,     C_{V} = molar heat capacity

                    M = molecular mass

               C_{v} = specific heat

Hence, calculate the value of C_{v} as follows.

                 C_{V} = M \times C_{v}

               8 \times 8.314 \times 10^{7} = 146.06 \times C_{v}

               C_{v} = 10.2 \times 10^{6} erg. K^{-1}. gm^{-1}

This means that value of isochoric specific heat is 10.2 \times 10^{6} erg. K^{-1}. gm^{-1}.

Yes, we have to assume ideal gas behavior because for ideal gas:

                         dU = nC_{v}dT

Whereas for real gases "\frac{an^{2}}{V^{2}}" has to be added here.

5 0
3 years ago
Can someone please help me with this one?
kkurt [141]

Answer:

to my own understanding I think it's 65 percent

7 0
3 years ago
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