<u>Thermal energy</u><u> from the room-temperature water will continuously flow to the boiling water.</u>
- The second law states, in a straightforward manner, that heat cannot naturally go "uphill."
- When a pan of boiling water and a pan of ice are in touch, the hot water cools and the ice melts and warms up.
<h3>
THE FIRST LAW OF THERMODYNAMICS</h3>
- Adiabatic Process - is a procedure that is carried out without the system's heat content changing.
- Water is heated to a temperature of 1000C during the boiling process, making it an isothermal process. As steam, the excess heat leaves the system.
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Answer:
<h2>15.25 N</h2>
Explanation:
A force of
is acting on a wagon along the road. The wagon weights
. Acceleration of the wagon is given as
.
Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.
Gravitational Force and Normal Reaction cancel out each other.
Net External Force = Mass of system/wagon
Acceleration of wagon

has a negative sign because it opposes the motion of the wagon.
∴ Frictional Force = 15.25 N
Apply Gay-Lussac's law:
P/T = const.
P = pressure, T = temperature, the quotient of P/T must stay constant.
Initial P and T values:
P = 180kPa, T = -8.0°C = 265.15K
Final P and T values:
P = 245kPa, T = ?
Set the initial and final P/T values equal to each other and solve for the final T:
180/265.15 = 245/T
T = 361K
Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance.
E = kQ / d²
k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m
Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²
Electric field at the test charge is 921600000 N/C
Answer:
A
Explanation:
It would not be C because prokaryotic cells don't have a nucleus. And if you're looking for a body in the cell that controls the nutrients and water it would be A.