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Verdich [7]
3 years ago
7

1.9 km converted to miles

Physics
1 answer:
Snowcat [4.5K]3 years ago
7 0
When you convet km to miles this is what you get 

1.18061
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Rosa pours a cup of boiling water into a pot of room-temperature water. According to the second law of thermodynamics, what will
11111nata11111 [884]

<u>Thermal energy</u><u> from the room-temperature water will continuously flow to the boiling water.</u>

  • The second law states, in a straightforward manner, that heat cannot naturally go "uphill."
  • When a pan of boiling water and a pan of ice are in touch, the hot water cools and the ice melts and warms up.

<h3>THE FIRST LAW OF THERMODYNAMICS</h3>
  • Adiabatic Process - is a procedure that is carried out without the system's heat content changing.
  • Water is heated to a temperature of 1000C during the boiling process, making it an isothermal process. As steam, the excess heat leaves the system.

Learn more about first law of thermodynamics brainly.com/question/3808473

#SPJ4

8 0
1 year ago
A force of 55N accelerates a 7.5kg wagon at 5.3 m/s^2 along a road. How large is the frictional force?
Varvara68 [4.7K]

Answer:

<h2>15.25 N</h2>

Explanation:

       A force of 55\text{ }N is acting on a wagon along the road. The wagon weights 7.5\text{ }kg. Acceleration of the wagon is given as 5.3\text{ }\frac{m}{s^{2}}.

       Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.

       Gravitational Force and Normal Reaction cancel out each other.

       Net External Force = Mass of system/wagon \times Acceleration of wagon

       F_{ext}-F_{friction}=(7.5\text{ }kg)\times(5.3\text{ }\frac{m}{s^{2}})=39.75\text{ }N\\55\text{ }N-F_{friction}=39.75\text{ }N\\F_{friction}=15.25\text{ }N

F_{friction} has a negative sign because it opposes the motion of the wagon.

∴ Frictional Force = 15.25 N

4 0
3 years ago
A motorist inflates the tires of her car to a pressure of 180 kPa on a day when the temperature is -8.0° C. When she arrives at
GuDViN [60]

Apply Gay-Lussac's law:

P/T = const.

P = pressure, T = temperature, the quotient of P/T must stay constant.

Initial P and T values:

P = 180kPa, T = -8.0°C = 265.15K

Final P and T values:

P = 245kPa, T = ?

Set the initial and final P/T values equal to each other and solve for the final T:

180/265.15 = 245/T

T = 361K

4 0
3 years ago
A test charge is placed at a distance of 2.5 × 10-2 meters from a charge of 6.4 × 10-5 coulombs. What is the electric field at t
Novosadov [1.4K]
Using the formula: E = kQ / d² where E is the electric field, Q is the test charge in coulomb, and d is the distance. 

E = kQ / d²

k = 9 x 10^9 N-m²/C²
Q = 6.4 x 10^-5 C
d = 2.5 x 10^-2 m

Substituting the given values to the equation, we have:
E = (9 x 10^9)(6.4 x 10^-5) / (2.5 x 10^-2) ²

Electric field at the test charge is 921600000 N/C
8 0
2 years ago
Read 2 more answers
In prokaryotic and eukaryotic cells the amount of water in the cell is kept at a steady state. The organelles
Len [333]

Answer:

A

Explanation:

It would not be C because prokaryotic cells don't have a nucleus. And if you're looking for a body in the cell that controls the nutrients and water it would be A.

3 0
3 years ago
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