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3 years ago

7

1.9 km converted to miles

1 answer:

Snowcat [4.5K]3 years ago

7 0

When you convet km to miles this is what you get

1.18061

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A 0.157-kg baseball moving at 21.2 m/s strikes the glove of a catcher. The glove recoils a distance of 10.7 cm.The magnitude of

san4es73 [151]

Answer:329.72 N

Explanation:

Given

mass of ball $m=0.157\ kg$

velocity of ball $v=21.2\ m/s$

glove recoil distance $d=10.7\ cm$

Energy associated with ball E=kinetic energy of ball

$E=\frac{1}{2}mv^2$

$E=\frac{1}{2}\times 0.157\times 21.2^2$

$E=35.28\ J$

Now if an average for is applied to stop the ball then work done by this force is equal to kinetic energy of the ball

$W=F_{avg}\cdot d=E$

$F_{avg}=\frac{E}{d}=\frac{35.28}{0.107}=329.72\ N$

6 0

3 years ago

Read 2 more answers

A child holds one end of a 33.0-meter long rope in her hand and moves it up-and-down to produce a sinusoidal wave by moving her

WITCHER [35]

Answer:

Wavelength=75 cm.

The wavelength well remain unchanged which is 75 cm.

Explanation:

The formula which will help us to answer the question is:

V=f*λ

Where:

V is the velocity

f is the frequency of wave

λ is the wave length

Now:

λ=V/f Eq (1)

The equation show's that wavelength is independent of the amplitude but it depends on the frequency and the velocity with which wave is moving.

The wavelength well remain unchanged which is 75 cm.

6 0

3 years ago

What is the force of a 12 kg rock falling at 9.8m/s/s

velikii [3]

F=W=mg
F=12*9.8

F=117.6Newtons

5 0

3 years ago

A 20kg bike accelerates at 10 m/s2. With what force was the person padeling?

Romashka-Z-Leto [24]

Formula:
F = ma
F: force (N) m: mass (kg) a: acceleration (m/s^2)

Solution:
F = ma
F = 20 × 10
= 200N

6 0

3 years ago

For a short time the missile moves along the parabolic path y=(18−2x2) km. If motion along the ground is measured as x=(4t−3) km

muminat

Answer with Explanation:

We are given that

$y=(18-2x^2) km$

$x=(4t-3)km$

Differentiate x and y w.r.t t

$\frac{dx}{dt}=4$

$\frac{dy}{dt}=-4x\frac{dx}{dt}$

$\frac{dy}{dt}=-4x\times 4=-16x=-16(4t-3)$

$v_x=\frac{dx}{dt}=4$

$v_y=\frac{dy}{dt}=-16(4t-3)$

Substitute t=1

$v_x=4$

$v_y=-16(4-3)=-16$

Magnitude of velocity= $\mid v\mid=\sqrt{v^2_x+v^2_y}$

$\mid v\mid=\sqrt{4^2+(-16)^2}=16.49 m/s$

Hence, the magnitude of the missile's velocity=16.49 m/s

$a_x=\frac{d(\frac{dx}{dt})}{dt}=\frac{d(4)}{dt}=0$

$a_y=\frac{d(\frac{dy}{dt})}{dt}=\frac{d(-16(4t-3))}{dt}=-64$

Substitute t=1

$a_x=0,a_y=-64$

$\mid a\mid=\sqrt{a^2_x+a^2_y}$

$\mid a\mid=\sqrt{0+(-64)^2}=64m/s^2$

Hence, the magnitude of acceleration when t=1 s= $64m/s^2$

3 0

2 years ago