1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Murrr4er [49]
3 years ago
13

A 0.157-kg baseball moving at 21.2 m/s strikes the glove of a catcher. The glove recoils a distance of 10.7 cm.The magnitude of

the average force applied by the ball on the glove is __.
Physics
2 answers:
tatuchka [14]3 years ago
7 0

The magnitude of average force applied by ball on glove is

|F_avg| =330N

Explanation:

Mass of baseball m = 0.157 kg

Initial velocity v_1 = 21.2 m/s

Final velocity v_f = 0 m/s

Distance moved before coming to rest

s = d = 10.7 cm = 0.107 m

V_f ^2 = V_i^2/2 s

= 0^2 - (21.2)^2/2* 0.107

a= 449.44 /0.214

a = -2100 m/s^2

a- acceleration of baseball

Average force applied by the ball on glove |F_avg| = m|a|

=0.157*2100

=329.7 N

|F_avg| =330 N

san4es73 [151]3 years ago
6 0

Answer:329.72 N

Explanation:

Given

mass of ball m=0.157\ kg

velocity of ball v=21.2\ m/s

glove recoil distance d=10.7\ cm

Energy associated with ball E=kinetic energy of ball

E=\frac{1}{2}mv^2

E=\frac{1}{2}\times 0.157\times 21.2^2

E=35.28\ J

Now if an average for is applied to stop the ball then work done by this force is equal to kinetic energy of the ball

W=F_{avg}\cdot d=E

F_{avg}=\frac{E}{d}=\frac{35.28}{0.107}=329.72\ N

You might be interested in
A girl pushes a cart with a force of 10 N. if the cart has a mass of 5 kg, what is its acceleration?
nikklg [1K]

Explanation:

Force=Mass*acceleration or F=MA. To find acceleration can be rewritten as A=F/M. If you input the numbers ypu can rewrite as A= 10N/5kg, A=2

The acceleration is 2 meters per sec.

8 0
3 years ago
A 2000 kg car moves along a horizontal road at speed vo
cluponka [151]

Answer:

The shortest possible stopping distance of the car is 175.319 meters.

Explanation:

In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:

\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a (Eq. 1)

\Sigma F_{y} = N-m\cdot g = 0 (Eq. 2)

After quick handling, we get that deceleration experimented by the car is equal to:

a = -\mu_{k}\cdot g (Eq. 3)

Where:

a - Deceleration of the car, measured in meters per square second.

\mu_{k} - Kinetic coefficient of friction, dimensionless.

g - Gravitational acceleration, measured in meters per square second.

If we know that \mu_{k} = 0.0735 and g = 9.807\,\frac{m}{s^{2}}, then deceleration of the car is:

a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )

a = -0.721\,\frac{m}{s^{2}}

The stopping distance of the car (\Delta s), measured in meters, is determined from the following kinematic expression:

\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a} (Eq. 4)

Where:

v_{o} - Initial speed of the car, measured in meters per second.

v - Final speed of the car, measured in meters per second.

If we know that v_{o} = 15.9\,\frac{m}{s}, v = 0\,\frac{m}{s} and a = -0.721\,\frac{m}{s^{2}}, stopping distance of the car is:

\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}

\Delta s = 175.319\,m

The shortest possible stopping distance of the car is 175.319 meters.

8 0
3 years ago
Which statements describe the image produced by a concave lens?check all that apply.
kotegsom [21]

<em>Answer:</em>

<em>The answers are: </em>

  • <em>A-which is the image is always right side up.</em>
  • <em>E-the image is virtual</em>

<em></em>

<em>Explanation: MY EXPLANATION IS YOU ARE WELCOME BIG DOG 100..</em>

<em></em>

<h2 />
7 0
3 years ago
Read 2 more answers
NGSS Physics
vovangra [49]
Answer: 3.5 seconds

EXPLANATION:

Using the formula:
v = u + at
And taking the upwards direction as positive, we have the following information:

u = 35 m/s
a = -10m/s^2 (this is acceleration due to gravity)

At the top of its path, the apple will have a velocity of 0 m/s, therefore:

v = 0m/s

Once you substitute everything into the formula, you get:

0 = 35 + (-10)t

Therefore, t = 35/10 = 3.5 seconds
6 0
3 years ago
‘The Universe is expanding.’ Justify this statement with the Big bang model of universe and Hubble’s Law.
Taya2010 [7]

Explanation:

The expansion of the universe is the increase in distance between any two given ... Metric expansion is a key feature of Big Bang cosmology, is modeled mathematically with the ...

7 0
2 years ago
Other questions:
  • What do scientist use to look at astronomical bodies?
    7·2 answers
  • Which of the following describes what needs to occur in order to reduce force while doing the same amount of work?
    6·1 answer
  • Cual es el modulo del vector diferencia (a - b) entre dos vectores que forman un angulo de 30° entre si y cuyos módulos son 2m y
    11·1 answer
  • A car climbs 10.0 kilometers up a hill that inclines 8.0 degrees. What is the car's vertical displacement?
    14·1 answer
  • The intensity of sunlight incident on the surface of a solar panel on your roof is 1000 W/m^2. Calculate the sunlight energy abs
    11·1 answer
  • Why would the time of flight depend on the angle of the launch
    10·1 answer
  • What is chronology?
    13·2 answers
  • A long time after the switch is closed, what is the voltage across the capacitor in terms of the supply voltage?
    13·1 answer
  • An object, which is at the origin at time t=0
    13·2 answers
  • A sound with a lot of energy is ____________________ than a sound with less energy.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!