Answer:
Explanation:
plate separation = 2.3 x 10⁻³ m
capacity C₁ = ε A / d
= ε A / 2.3 x 10⁻³
C₂ = ε A / 1.15 x 10⁻³
=
a ) when charge remains constant
energy =
q is charge and C is capacity
energy stored initially E₁=
energy stored finally E₂ =
=
=
=
= 4.19 J
b )
In this case potential diff remains constant
energy of capacitor = 1/2 C V²
energy is proportional to capacity as V is constant .
= 16.76 .
Explanation:
Given that,
Capacitor = 30μC
Resistor = 49.0Ω
Voltage = 30.0 V
Frequency = 60.0 Hz
We need to calculate the impedance
Using formula of impedance
.....(I)
We need to calculate the value of
Using formula of
Put the value of into the formula of impedance
(a). We need to calculate the rms current in the circuit
Using formula of rms current
The rms current in the circuit is 0.30 A.
(b). We need to calculate the rms voltage drop across the resistor
Using formula of rms voltage
Put the value into the formula
The rms voltage drop across the resistor is 14.7 V
(c). We need to calculate the rms voltage drop across the capacitor
Using formula of rms voltage
The rms voltage drop across the capacitor is 26.53 V.
Hence, This is the required solution.