Answer:
2271.16N/C upward
Explanation:
The diagram well illustrate all the forces acting on the mass. The weight is acting downward and the force is acting upward in other to balance the weight.since the question says it is motionless, then indeed the forces are balanced.
First we determine the downward weight using
![W=mg\\g=9.81m/s^{2}](https://tex.z-dn.net/?f=W%3Dmg%5C%5Cg%3D9.81m%2Fs%5E%7B2%7D)
Hence for a mass of 3.82g 0r 0.00382kg we have the weight to be
![W=0.00382kg*9.81m/s^{2}](https://tex.z-dn.net/?f=W%3D0.00382kg%2A9.81m%2Fs%5E%7B2%7D)
![W=0.0375N](https://tex.z-dn.net/?f=W%3D0.0375N)
To calculate the electric field,
![E=f/q\\E=0.0375/16.5*10^{-6} \\E=2271.16N/C](https://tex.z-dn.net/?f=E%3Df%2Fq%5C%5CE%3D0.0375%2F16.5%2A10%5E%7B-6%7D%20%5C%5CE%3D2271.16N%2FC)
Since the charge on the mass is negative, in order to generate upward force, there must be a like charge below it that is repelling it, Hebce we can conclude that the electric field lines are upward.
Hence the magnitude of the electric force is 2271.16N/C and the direction is upward
<em>There are some placeholders in the expression, but they can be safely assumed</em>
Answer:
(a) ![f=1617.9\ Hz](https://tex.z-dn.net/?f=f%3D1617.9%5C%20Hz)
(b) ![T=0.618\ ms](https://tex.z-dn.net/?f=T%3D0.618%5C%20ms)
(c) ![A=20 \ Volts](https://tex.z-dn.net/?f=A%3D20%20%5C%20Volts)
(d) ![\varphi=60^o](https://tex.z-dn.net/?f=%5Cvarphi%3D60%5Eo)
Explanation:
<u>Sinusoidal Waves
</u>
An oscillating wave can be expressed as a sinusoidal function as follows
![V(t)&=A\cdot \sin(2\pi ft+\varphi )](https://tex.z-dn.net/?f=V%28t%29%26%3DA%5Ccdot%20%5Csin%282%5Cpi%20ft%2B%5Cvarphi%20%29)
Where
![A=Amplitude](https://tex.z-dn.net/?f=A%3DAmplitude)
![f=frequency](https://tex.z-dn.net/?f=f%3Dfrequency)
![\varphi=Phase\ angle](https://tex.z-dn.net/?f=%5Cvarphi%3DPhase%5C%20%20angle)
The voltage of the question is the sinusoid expression
![V(t)=20cos(5\pi\times 103t+60^o)](https://tex.z-dn.net/?f=V%28t%29%3D20cos%285%5Cpi%5Ctimes%20103t%2B60%5Eo%29)
(a) By comparing with the general formula we have
![f=5\pi\times 103=1617.9\ Hz](https://tex.z-dn.net/?f=f%3D5%5Cpi%5Ctimes%20103%3D1617.9%5C%20Hz)
![\boxed{f=1617.9\ Hz}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%3D1617.9%5C%20Hz%7D)
(b) The period is the reciprocal of the frequency:
![\displaystyle T=\frac{1}{f}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20T%3D%5Cfrac%7B1%7D%7Bf%7D)
![\displaystyle T=\frac{1}{1617.9\ Hz}=0.000618\ sec](https://tex.z-dn.net/?f=%5Cdisplaystyle%20T%3D%5Cfrac%7B1%7D%7B1617.9%5C%20Hz%7D%3D0.000618%5C%20sec)
Converting to milliseconds
![\boxed{T=0.618\ ms}](https://tex.z-dn.net/?f=%5Cboxed%7BT%3D0.618%5C%20ms%7D)
(c) The amplitude is
![\boxed{A=20 \ Volts}](https://tex.z-dn.net/?f=%5Cboxed%7BA%3D20%20%5C%20Volts%7D)
(d) Phase angle:
![\boxed{\varphi=60^o}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cvarphi%3D60%5Eo%7D)
Most of the radiation, however, is absorbed by the earth's surface. ... Every surface on earth absorbs and reflects energy at varying degrees, based on its color and texture. Dark-colored objects absorb more visible radiation; light-colored objects reflect more visible radiation.
Explanation:
1.
the rate at which something occurs over a particular period of time or in a given sample.
"an increase in the frequency of accidents due to increased overtime"
2.
the rate per second of a vibration constituting a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light).
"different thicknesses of glass will absorb different frequencies of sound"