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3 years ago

Can a tank of oxygen gas ever be half empty? explain

2 answers:

3 0

No, it is practically very unlikely situation. Oxygen is a gas and gas has no shape it occupies the shape of the container. moreover, according to the kinetic theory of gases, the particles of gas move in random motion occuping the space. The particles move randomly and keep on colliding with each other. Therefore, it is not correct to say that a tank of oxygen gas can ever be half empty.

MatroZZZ [7]3 years ago

3 0

The answer is yes. The compacted air moves to the sifter bed channels. The strainer bed channel assumes an imperative part, as the gadget expels the nitrogen from the air. After air is first compacted in the concentrator, it is constrained into the primary strainer bed. Oxygen is sent into the item tank.

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If we reverse the reaction to read Z + Q → X + Y, the +ΔH would be a -ΔH. Does this indicate that heat is given off or absorbed

grin007 [14]

Answer:

Reactants.

Step-by-step explanation:

The equation for the reverse reaction is

Z + Q ⟶ X + Y; ΔH < 0

A negative ΔH indicates that the energy has been given off.

The products X + Y are at a lower energy level than the reactants Z + Q, and the excess energy has been transferred to the surroundings.

8 0

4 years ago

Read 2 more answers

Predict the bond present between carbon and hydrogen in polyethylene

sweet-ann [11.9K]

It is an alkene: CnH2n (n=number of the atoms of carbon)
in ethylene there are two carbons so:
C2H4 just like the picture

6 0

4 years ago

Phosphorus pentachloride decomposes according to this equation. PCl5(g) equilibrium reaction arrow PCl3(g) + Cl2(g) An equilibri

melisa1 [442]

Answer:

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

Explanation:

The equilibrium constant will remain the same irrespective of the amount of reactant taken.

Let us calculate the equilibrium constant of the reaction.

Kc= $\frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}$

Let us calculate the moles of each present at equilibrium

$moles=\frac{mass}{molarmass}$

molar mass of PCl₅=208

molar mass of PCl₃=137

molar mass of Cl₂=71

moles of PCl₅ = $\frac{mass}{molarmass}=\frac{4.13}{208}=0.02$

moles of PCl₃= $\frac{mass}{molarmass}=\frac{8.87}{137}=0.06$

moles of Cl₂ = $\frac{mass}{molarmass}=\frac{2.90}{71}=0.04$

the volume is 5 L

So concentration will be moles per unit volume

Putting values

Kc = $\frac{\frac{0.06}{5}\frac{0.04}{5}}{\frac{0.02}{5}}=0.024$

Now if the same moles are being transferred in another beaker of volume 2L then there will change in the concentration of each as follow

$PCl_{5}--->PCl_{3}+Cl_{2}$

Initial 0.02 0.06 0.04

Change -x +x +x

Equilibrium 0.02-x 0.06+x 0.04+x

Conc. (0.02-x)/2 (0.06+x)/2 (0.04+x)/2

Putting values

0.024 = $\frac{(0.06+x)(0.04+x)}{(0.02-x)2}$

Solving

$(0.024(2)(0.02-x)=(0.06+x)(0.04+x)$

$0.00096-0.048x=0.0024+x^{2}+0.1x$

$0.148x+x^{2}+0.00144=0$

x = -0.01

so the new moles of

PCl₅ = 0.02 + 0.01 =0.03

PCl₃ = 0.06-0.01 = 0.05

Cl₂ = 0.04-0.01 = 0.03

mass of each will be:

mass= moles X molar mass

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

5 0

4 years ago

Balance the Following Equations: SiCl4 + H2O = SiO2 + HCl

Dmitry [639]

Answer:

SiCl4 + H2O = SiO2 + HCl

Reactant. product

Si = 1 atom Si = 1 atom

Cl = 4 atom Cl = 1 atom

H = 2 atom H = 1 atom

O = 1 atom O = 2 atom

SiCl4. + 2H2o = SiO2 + 4hcl

Reactant. product

Si = 1 atom Si = 1 atom

Cl = 4 atom Cl = 4 atom

H = 4 atom H = 4 atom

O = 2 atom O = 2 atom

Balanced chemical equation.

4 0

3 years ago

6. Positive uses of radioactive decay used by humans would not include

spin [16.1K]

Answer:

Explanation:

All are good

7 0

3 years ago