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xeze [42]
3 years ago
10

PLEASE HELP ME WITH THIS I ONLY HAVE 8 MINUTES I will give you extra points . NUMBER 6

Chemistry
2 answers:
Veronika [31]3 years ago
6 0

Answer:

3 mass instincts. If you look at the scale you can they evenly sometimes line up with a line. Whenever a huge instinct occurred the lines were really high, but whenever they were little instincts on the scale the lines would go down

Explanation:

scoray [572]3 years ago
4 0
A mass extinction is the rapid decrease in something. so anytime that graph goes down drastically would be a mass extinction
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If you purchased 0.610 μCi of sulfur-35, how many disintegrations per second does the sample undergo when it is brand new?Expres
ASHA 777 [7]

Answer:

the sample undergo 1.67 \times 10^5  disintegrations per second.

Explanation:

Given:

The amount of sulphur purchased is 0.671 μCi

To find:

disintegrations per second = ?

Solution:

Some of the conversions are

1 Ci = 3.8 \times 10^{10} Bq

1 rad = 0.01 Gy

1Gy = 1 j/kg tissue

1 rem = 0.01 Sv

1Sv = 1 j/Kg

Using these conversions,

The decay rate of this sample is calculated as

0.671 \mu C i \times \frac{1 \mu C i}{10^{6}} \mu C i \times \frac{0.671 \times 10^{10}}{1 \mu C i}

= 1.67 \times 10^5 disintegrations per second

7 0
4 years ago
I would appreciate some help please ᕕ( ᐛ )ᕗ
ElenaW [278]

Answer:

dont know, will let uk in 2 mins

Explanation:

3 0
3 years ago
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Whats does the sun and the solar system orbit plz helo me its for a test
madreJ [45]
The sun does not orbit anything everything orbits the sun and I don't think the solar system orbits anything I'm sorry
4 0
3 years ago
Calculate the total energy, in kilojoules, that is needed to turn a 46 g block
gogolik [260]

<u>Answer:</u> The amount of heat absorbed is 141.004 kJ.

<u>Explanation:</u>

In order to calculate the amount of heat released while converting given amount of steam (gaseous state) to ice (solid state), few processes are involved:

(1): H_2O (s) (-25^oC, 248K) \rightleftharpoons H_2O(s) (0^oC,273K)

(2): H_2O (s) (0^oC, 273K) \rightleftharpoons H_2O(l) (0^oC,273K)  

(3): H_2O (l) (0^oC, 273K) \rightleftharpoons H_2O(l) (100^oC,373K)

(4): H_2O (l) (100^oC, 373K) \rightleftharpoons H_2O(g) (100^oC,373K)

Calculating the heat absorbed for the process having the same temperature:

q=m\times \Delta H_{(f , v)}       ......(i)

where,

q is the amount of heat absorbed, m is the mass of sample and \Delta H_{(f , v)} is the enthalpy of fusion or vaporization

Calculating the heat released for the process having different temperature:

q=m\times C_{s,l}\times (T_2-T_1)      ......(ii)

where,

C_{s,l} = specific heat of solid or liquid

T_2\text{ and }T_1 are final and initial temperatures respectively

  • <u>For process 1:</u>

We are given:

m=46g\\C=2.108J/g^oC\\T_2=0^oC\\T_1=-25^oC

Putting values in equation (i), we get:

q_1=46g\times 2.108J/g^oC\times (0-(-25))\\\\q_1=2424.2J

  • <u>For process 2:</u>

We are given:

m=46g\\\Delta H_{fusion}=334J/g

Putting values in equation (i), we get:

q_2=46g\times 334J/g\\\\q_2=15364J

  • <u>For process 3:</u>

We are given:

m=46g\\C=4.186J/g^oC\\T_2=100^oC\\T_1=0^oC

Putting values in equation (i), we get:

q_3=46g\times 4.186J/g^oC\times (100-0)\\\\q_3=19255.6J

  • <u>For process 4:</u>

We are given:

m=46g\\\Delta H_{vap}=2260J/g

Putting values in equation (i), we get:

q_4=46g\times 2260J/g\\\\q_4=103960J

Calculating the total amount of heat released:

Q=q_1+q_2+q_3+q_4

Q=[(2424.2)+(15364)+(19255.6)+(103960)]

Q=141003.8J=141.004kJ                  (Conversion factor: 1 kJ = 1000J)

Hence, the amount of heat absorbed is 141.004 kJ.

7 0
3 years ago
I need help with this ASAP PLEASE
Artemon [7]

439.3 g CO2

Explanation:

First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:

3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)

= 9.981 mol CO2

Use the molar mass of CO2 to determine the # of grams of CO2:

9.981 mol CO2 x (44.01 g CO2/1 mol CO2)

= 439.3 g CO2

5 0
3 years ago
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