What volume of a 3.0 M stock solution of H2SO4 is needed to prepare 2.8 L of a 1.6 M H2SO4 solution?
2 answers:
<u>Answer:</u> The volume of stock solution needed is 1.5 L
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:

where,
are the molarity and volume of the stock solution
are the molarity and volume of diluted solution
We are given:

Putting values in above equation, we get:

Hence, the volume of stock solution needed is 1.5 L
Use M1V1 = M2V2 to solve
3(V1) = 2.8 * 1.6
3(V1) = 4.48
V1 = 1.493 L of stock solution
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