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3 years ago

ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST

1 answer:

6 0

Average atomic mass = .374 ( 184.953 amu ) + .626 ( 186.958 amu ) =
186.207 amu
Hope this helps x
would love to have brainliest if it is right! :)

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Avogradro's number is the number of particles in one gram of carbon- 12 atom true or false?

LiRa [457]

Answer:

True

Explanation:

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

5 0

2 years ago

Hemoglobin in your blood does not use elemental iron. It uses iron in the form of Fe2+(aq).

valina [46]

Explanation:

Balanced chemical reaction equation will be as follows.

$2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)$

In human body, the neutral iron changes into $Fe^{2+}$ (aq) cation. There will be an oxidation-half reaction and a reduction-half reaction. Equations for this reaction are as follows.

Oxidation: 2Fe^{2+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + 2e^{-}[/tex] .... (1)

Reduction: $2H^{+}(aq) + 2e^{-} \rightleftharpoons H_{2}(g)$ ...... (2)

On adding both equation (1) and (2), the overall reaction equation will be as follows.

$2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)$

Therefore, neutral iron is a part of Heme - b group of Hemoglobin and in an aqueous solution it dissolutes as a part of Heme group. Hence, then it becomes an $Fe^{2+}$ cation.

3 0

2 years ago

To indicate the pH of a substance, one can use a dye that is both an acid and that appears as different colors in its protonated

PIT_PIT [208]

Answer:

<em>The pH of the solution is 7.8</em>

Explanation:

The concentration of the solution is 0.001M and the dye could be in its protonated and deprotonated forms. If the concentration of the protonated form [HA] is 0.0002 M the concentration of the deprotonated form will be the subtraction between the concentration of the bye and the concentration of the protonated form:

[A-] = 0.001M - 0.0002M = 0.0008M

Also, the Henderson-Hasselbalch equation is

$pH = pKa + Log \frac{[A^{-}]}{[HA]}$

this equation shows the dependency between the pH of the solution, the pKa and the concentration of the protonated and deprotonated forms. Thus, replacing in the equation

$pH = 7.2 + Log \frac{0.0008M}{0.0002M} = 7.8$

3 0

2 years ago

A 4.0 L container holds a sample of hydrogen gas at 306 K and 150 kPa. If the pressure increases to 300 kPa and the volume remai

riadik2000 [5.3K]

Answer:

612 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 306 K

Initial pressure (P₁) = 150 kPa

Final pressure (P₂) = 300 kPa

Volume = 4 L = constant

Final temperature (T₂) =?

Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

150 / 306 = 300 / T₂

Cross multiply

150 × T₂ = 306 × 300

150 × T₂ = 91800

Divide both side by 150

T₂ = 91800 / 150

T₂ = 612 K

Thus, the new temperature of the gas is 612 K

4 0

2 years ago

I'm having trouble balancing these. Can you help me

AlekseyPX

Answer:

Oh Okay

I hope u have a better rest of ur day

4 0

2 years ago