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valentinak56 [21]
3 years ago
7

ASAP MULTIPLE CHOICE WILL MARK BRAINLIEST

Chemistry
1 answer:
QveST [7]3 years ago
6 0
Average atomic mass = .374 ( 184.953 amu ) + .626 ( 186.958 amu ) =
186.207 amu
Hope this helps x
would love to have brainliest if it is right! :)
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The element thallium is 70% thallium-205 and 30% thallium-203. Calculate its relative atomic mass to 1 decimal place.
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Answer:

answer-

The relative atomic mass = 204.4

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Thallium -203 = 30%

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relative mass of thallium = (20440)/100

relative mass of thallium = 204.40 amu

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How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?
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Answer : The number of moles of solute Ca(OH)_2 is, 0.0788 moles.

Explanation : Given,

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\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}

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0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}

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Therefore, the number of moles of solute Ca(OH)_2 is, 0.0788 moles.

7 0
3 years ago
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