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alex41 [277]
3 years ago
6

How many grams of Oz would be needed to produce 1.875 moles of aluminum?

Chemistry
1 answer:
eimsori [14]3 years ago
5 0

Answer:

1.4063 moles of oxygen are required

Explanation:

Based on the chemical equation:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of aluminium react with 3 moles of oxygen.</em>

<em />

To solve this question we need to convert the moles of aluminium to moles of oxygen using the chemical reaction:

1.875 moles Al * (3 moles O₂ / 4 moles Al) =

<h3>1.4063 moles of oxygen are required</h3>
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3 years ago
When considering metal complexation with EDTA, if you are comparing 2 metals, the metal with a higher ____________ will react wi
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hope this helped

7 0
4 years ago
? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







</span>
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