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alex41 [277]
3 years ago
6

How many grams of Oz would be needed to produce 1.875 moles of aluminum?

Chemistry
1 answer:
eimsori [14]3 years ago
5 0

Answer:

1.4063 moles of oxygen are required

Explanation:

Based on the chemical equation:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of aluminium react with 3 moles of oxygen.</em>

<em />

To solve this question we need to convert the moles of aluminium to moles of oxygen using the chemical reaction:

1.875 moles Al * (3 moles O₂ / 4 moles Al) =

<h3>1.4063 moles of oxygen are required</h3>
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It’s ionic bond based on electrons gain/loss.
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4. Cuál es la aplicación de las reacciones de óxido-reducción en la vida diaria y en la industria?
12345 [234]

Answer:

<em>Dentro de las aplicaciones de la óxido-reducción se pueden encontrar:</em>

  1. <u><em>La obtención del aluminio a partir de la alúmina y la electrolisis.</em></u>
  2. <u><em>La obtención de cloro, hidrógeno e hidróxido de sodio a partir del cloruro de sodio y la electrolisis.</em></u>
  3. <u><em>La combustión interna de un motor a gasolina u otro combustible fósil.</em></u>
  4. <u><em>Las termoeléctricas, las cuales para generar energía realizan combustión de carbón.</em></u>
  5. <u><em>La galvanoplastia, donde para evitar la corrosión de un metal se recubre con otro metal más resistente, por ejemplo: el recubrimiento del acero con zinc.</em></u>
  6. <u><em>La pilas o baterías de las cuales se obtiene energía química</em></u><em>.</em>

Explanation:

<em>Como puedes ver en la respuesta, la óxido-reducción tiene diversas aplicaciones en la vida moderna, desde todos los tipos de combustión los cuales sirven para brindar energía o movilizarte, hasta todas las funciones que se le ha dado a la electrolisis y a la obtención de la energía por medios químicos, incluso se puede considerar una aplicación de la óxido-reducción la incorporación de antioxidantes en los alimentos, los cuales disminuyen la velocidad de descomposición de los mismos. </em>

3 0
3 years ago
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)
stiv31 [10]

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

What about ;

? (x)   :  1

We cross multiply;

3x = 1 * 1

X = 1/3

We evaluate the same for O₂;

O₂(g) : CO₂(g)

5 :     3

What about

? (x) :     1

3x = 5 * 1

x = 5/3

Learn More:

For more on evaluating moles in chemical reactions check out;

brainly.com/question/13967925

brainly.com/question/13969737

#LearnWithBrainly

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What phase of matter changes volume when moved from one container to another ?
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Answer:

gas

Explanation:

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