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dimulka [17.4K]
3 years ago
15

At a certain temperature, O2 molecules move at an average velocity of 480 m/s. At that same temperature what would be the veloci

ty of He atoms?
Chemistry
1 answer:
german3 years ago
4 0

Answer:

r_{He}=169.7m/s

Explanation:

Hello there!

In this case, since this problem can be understood via the Graham's law, which states that states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight, which can be extrapolated to the rate, we have:

\frac{r_{O_2}}{r_{He}} =\sqrt{\frac{M_{He}}{M_{O_2}} }

Thus, since the molar mass of helium is 4.0 g/mol and that of oxygen is 16.0 g/mol, we solve for the average velocity of helium as shown below:

r_{He}=r_{O_2}\sqrt{\frac{M_{He}}{M_{O_2}} }\\\\r_{He}=480m/s\sqrt{\frac{4.0g/mol}{32.0g/mol} }\\\\r_{He}=169.7m/s

Regards!

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For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this
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Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

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O = -2                            O = -2

Ag = +1                         Ag = 0

NO2– -----> NO3– ………oxidation half reaction

Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

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Step 3) Balance the O by adding 1 H2O for 1 O

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Step 4) Balance the H by adding H+

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     Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

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     Ag+ + 1e------> Ag(s)

Step 6) Balance the electron in both half reaction

    NO2– + H2O -----> NO3– + 2H+ + 2e-

     2 Ag+ + 2e------> 2 Ag(s)

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