Question

The radius of an atom of gold (Au) is about 1.35 Å. How many gold atoms would have to be lined up to span 5.0 mm ?

Answer 1

1.851.10⁷ gold atoms would have to be lined up to span 5.0 mm

Further explanation

There are 7 main quantities that have been determined based on international standards, namely:  

• 1. Length, meters (m)
• 2. Time, second (s)
• 3. Mass, kilograms (kg)
• 4. Temperature, kelvin (K)
• 5. Light intensity, candela (cd)
• 6. Electric current, ampere (A)
• 7. Amount of substance, mol (m)

The length indicate the distance between two points in a place  

The symbol is usually expressed in l, length  

Length measurement can be used by several measuring instruments such as ruler, caliper length, meter, screw micrometer  

The main length unit consists of 7 units :

• Kilometer, km
• Hectometer, hm
• Dekameter, dam
• Meter, m
• Decimeter, dm
• centimeter, cm
• millimeters, mm

Each one unit descends then multiplied by 10, and if one unit increases then divided by 10  

For 1 Â (angstrom) equal to 10⁻⁷ mm

The radius of an atom of gold (Au) is about 1.35 Å

so the diameter = 1.35 x 2 = 2.7 Å = 2.7.10⁻⁷ mm

to be lined up to span 5.0 mm requires gold atoms :

amount of gold atom : 5.0 : 2.7.10⁻⁷ mm = 1.851.10⁷

Learn more

book thickness in cm

brainly.com/question/8540796

The mass of A standard baseball

brainly.com/question/4576804

the quantity of 0.0075 meters expressed in centimeters

brainly.com/question/2867118

Keywords: gold atom, diameter, millimeters, angstrom(Å)

Answer 2

$r=1,35 \AA\\ d=2,7 \AA=2,7*10^{-10}m\\\\ 5mm=0,005m=5*10^{-3}m\\\\ Au_{atoms}=\frac{5*10^{-3}m}{2,7*10^{-10}m}=1,852*10^{-3-(-10)}m=1,852*10^{7}m$