The radius of an atom of gold (Au) is about 1.35 Å. How many gold atoms would have to be lined up to span 5.0 mm ?
2 answers:
1.851.10⁷ gold atoms would have to be lined up to span 5.0 mm
<h3>Further explanation</h3>There are 7 main quantities that have been determined based on international standards, namely:
- 1. Length, meters (m)
- 2. Time, second (s)
- 3. Mass, kilograms (kg)
- 4. Temperature, kelvin (K)
- 5. Light intensity, candela (cd)
- 6. Electric current, ampere (A)
- 7. Amount of substance, mol (m)
The length indicate the distance between two points in a place
The symbol is usually expressed in l, length
Length measurement can be used by several measuring instruments such as ruler, caliper length, meter, screw micrometer
The main length unit consists of 7 units :
- Kilometer, km
- Hectometer, hm
- Dekameter, dam
- Meter, m
- Decimeter, dm
- centimeter, cm
- millimeters, mm
Each one unit descends then multiplied by 10, and if one unit increases then divided by 10
For 1 Â (angstrom) equal to 10⁻⁷ mm
The radius of an atom of gold (Au) is about 1.35 Å
so the diameter = 1.35 x 2 = 2.7 Å = 2.7.10⁻⁷ mm
to be lined up to span 5.0 mm requires gold atoms :
amount of gold atom : 5.0 : 2.7.10⁻⁷ mm = 1.851.10⁷
<h3>Learn more </h3>book thickness in cm
The mass of A standard baseball
the quantity of 0.0075 meters expressed in centimeters
Keywords: gold atom, diameter, millimeters, angstrom(Å)
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