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mote1985 [20]
3 years ago
13

Theoretically, how many moles of carbonic acid will be produced by 3.00 g sample of NaHCO3?

Chemistry
1 answer:
Kryger [21]3 years ago
7 0
NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol 

Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27% 

3.0 g* .2727 = 0.8211 grams of sodium in sample of NaHCO3 

0.8211 grams Na + 1.266 grams Cl = 2.087 grams
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ollegr [7]

Answer:

1s^22s^22p^3

Explanation:

Nitrogen has the atomic number = 7

So, No. of electrons = 7

<u><em>Electronic Configuration:</em></u>

1s^22s^22p^3

<u>Remember that:</u>

s sub shell holds upto 2 electrons while p sub shell upto 6

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3 years ago
What is the total number of oxygen atoms on the right-hand side of this chemical equation?
vivado [14]

The chemical equation is

Cu(s) +4HNO3(aq) ⇒ Cu(NO3)2(aq) + 2NO2(g) + 2H2O(g)

Answer:

12

Explanation:

In the right hand side of the equation, there are three compound which contains O2, which are;

Cu(NO3)2 , number of oxygen atoms =3*2 =6

2NO2, number of oxygen atoms = 2*2=4

2H2O, number of oxygen atoms =2*1=2

Total number of oxygen atoms on the right side of equation = 6+4+2 =12

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Explain why vegetables last longer in a fridge.
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6 0
2 years ago
Read 2 more answers
What are deltaTb and deltaTf for an aqueous solution that is 1.5g nacl in 0.250kg h2o? Given Kb=0.51 C/m and kr=1.86 C/m
bulgar [2K]

Answer:

T_f for given question is 2.79 and T_b is 0.52

\Delta T_b = I \times K_b \times m {i- vant hoff’s constant ; Kb- constant ; m molarity }

M = no. of moles of the solute present in one kg of solution

Let the weight of amount of solute be “w” and its molecular mass be “M”

Let the mass of the solvent in the given question be “x”

\Delta T_b = I \times K_b \times (w/M)/ x

\Delta T_b = I \times K_b \times w/Mx

\Delta T_b = 1 \times 0.51 \times1.5/(0.250 \times 58.44) = 0.052

\Delta T_f = M \times K_f = 1.86 \times 1.5 = 2.79

4 0
3 years ago
Mannoheptulose is a sugar found in avocados. If each C-C bond contains 76 kcal of energy and each C-H bond contains 91 kcal, how
nadya68 [22]

Answer:

Total Kcal energy produced in the catabolism of mannoheptulose = 1184 Kcal

Explanation:

The molecular formula of mannoheptulose is C₇H₁₄O₇.

The structure is as shown in the attachment below.

Number of C-C bonds present in mannoheptulose = 6

Number of C-H bonds present in mannoheptulose = 8

Since the each C-C bond contains 76 Kcal of energy,

Amount of energy present in six C-C bonds = 6 * 76 = 456 Kcal

Also, since each C-H bond contains 91 Kcal of energy;

amount of energy present in eight C-H bonds = 8 * 91 = 728 Kcal

Total Kcal energy produced in the catabolism of mannoheptulose = 456 + 728 = 1184 Kcal

6 0
2 years ago
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