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3 years ago

Theoretically, how many moles of carbonic acid will be produced by 3.00 g sample of NaHCO3?

1 answer:

7 0

NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol

Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27%

3.0 g* .2727 = 0.8211 grams of sodium in sample of NaHCO3

0.8211 grams Na + 1.266 grams Cl = 2.087 grams

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