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ohaa [14]
3 years ago
14

How does adding a non-volatile solute to a pure solvent affect the boiling point of the pure solvent?

Chemistry
2 answers:
Bogdan [553]3 years ago
7 0

Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering. The correct answer is the second option. <span>The solvent will have a higher boiling point.</span>

andriy [413]3 years ago
5 0

Answer:

The correct answer is The solvent will have a higher boiling point

Explanation:

This question will be better understood with the knowledge of colligative property. The colligative properties of a solution are properties that are determined by the concentration of solute in the solution and not the identity of the solute. There are four colligative properties and one of them has been presented in the question.

Consider this common example, when a non-volatile solute like salt is added to a pure solvent like water, the boiling point of the solvent (which is water) becomes increased hence the colligative property here is that, <u><em>the solute causes the elevation/increase in the boiling point of the solvent</em></u>. This is the reason why pure water will boil earlier than an aqueous salt solution (like ocean water).

Thus, from the question, it can be said that when the non-volatile solute is added to the solvent, the solvent will have a higher boiling point.

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A 75 g piece of gold (Au) at 1000 K is dropped into 200 g of H2O at 300K in an insulatedcontainer at 1 bar. Calculate the temper
Arturiano [62]

Answer:

the final temperature is T final = 308 K

Explanation:

since all heat released by gold is absorbed by water

Q gold + Q water = Q surroundings =0 (insulated)

Assuming first that no evaporation of water occurs , and denoting g as gold and w as water , then

Q gold = m g*cp g* ( T final - T initial g)

Q gold = m w*cp w* ( T final - T initial w)

where

m= mass

cp = specific heat capacity

T final = final temperature

T initial g and T initial w =  initial temperature of gold and water respectively

thus

Q gold + Q water = 0

m g*cp g* ( T final - T initial g) + m w*cp w* ( T final - T initial w) =0

m g*cp g* T final + m w*cp w* T final =  m g*cp g* T initial g+ m w*cp w* T initial w

T final = (m g*cp g* T initial g+ m w*cp w* T initial w)/(m g*cp g+ m w*cp w)

replacing values and assuming cp w = 1 cal/gK = 4.816 J/gK and cp g = 0.129 J/gK (from tables), then

T final =  (75 g*0.129 J/gK* 1000 K + 200 g * 4.816 J/gK * 300 K )/(75 g*0.129 J/gK*+ 200 g * 4.816 J/gK ) = 308 K

T final = 308 K

since T boiling water = 373 K and T final = 308 K , we confirm that water does not evaporate

therefore the final temperature is T final = 308 K

3 0
3 years ago
A home remodeling company charges $10 per square yard for installing new carpets. What is the cost for installing a carpet for a
balu736 [363]

Answer:

$200.0 is the cost for installing a carpet for a room that measures 12.0 feet by 15.0 feet.

Explanation:

Length of the room = l = 15.0 ft = \frac{15.0}{3} yard=5.0 yard

Width of the room = w = 12.0 ft = \frac{12.0}{3} yard=4.0 yard

(1 yard = 3 feet)

Area of the room = l × w = 4.0 yard\times 5.0 yard = 20.0 yard^2

Cost for installing a carpet for a room = $10 per square yard

Cost for installing a carpet for a room wit area 20.0 square yard :

20.0 yard^2\times $10/ yard^2=$200.0

$200.0 is the cost for installing a carpet for a room that measures 12.0 feet by 15.0 feet.

7 0
3 years ago
When the gases dihydrogen monosulfide and oxygen react, they form the gases sulfur dioxide and water vapor. Write the balanced c
Anna35 [415]
2(H2S) + 3(O2) -> 2(SO2) + 2(H2O)
7 0
3 years ago
The rate of decomposition of acetaldehyde, CH_3 CHO(g), into CH_4(g) and CO(g) in the presence of I_2(g) at 800 K follows the ra
FrozenT [24]

Answer:

Explanation:

Catalyst is I2 . Because I2 is reacted with starting material in step 1 and generated in second step

Rate limiting step is step 1. Because in rate equation CH3CHO and I2 is mentioned. Hence the overall rate of reaction is depending CH3CHO and I2. Rate limiting step is step 1

5 0
3 years ago
C + 2H2 -&gt; CH4
ankoles [38]

Answer:

<u>C) 4</u>

Explanation:

<u>The reaction</u> :

  • C (s) + 2H₂ (g) ⇒ CH₄ (g)

       12g      4g             16g

Hence, based on this we can say that : <u>2 moles of hydrogen gas are needed to produce 16g of methane.</u>

<u />

<u>For 32g of methane</u>

  • Number of moles of H₂ = 32/16 × 2
  • Number of moles of H₂ = <u>4</u>
4 0
2 years ago
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