Answer:
We need 0.375 mol of CH3OH to prepare the solution
Explanation:
For the problem they give us the following data:
Solution concentration 0,75 M
Mass of Solvent is 0,5Kg
knowing that the density of water is 1g / mL, we find the volume of water:

Now, find moles of
are needed using the molarity equation:
therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH, resulting in a concentration of 0,75M
Answer: I HOPE THIS HELPS, HAVE A GREAT EARLY HALLOWEEN
Explanation:
PubChem CID: 1084
Molecular Formula: S2O3(2−) or O3S2-2
Synonyms: Thiosulphate THIOSULFATE ION sulfurothioate UNII-LLT6XV39PY Thiosulfate (S2O32-) More...
Molecular Weight: 112.13 g/mol
a. True.
There is always an equilibrium of the type
NH₃⁺CHRCOOH ⇌ NH₃⁺CHRCOO⁻ ⇌ NH₂CHRCOO⁻
The compound is <em>always in an ionized form</em>.
There are no unionized NH₂CHRCOOH molecules in the solution.
Answer is only B.
<span>it becomes more stable</span>