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ohaa [14]
3 years ago
14

How does adding a non-volatile solute to a pure solvent affect the boiling point of the pure solvent?

Chemistry
2 answers:
Bogdan [553]3 years ago
7 0

Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering. The correct answer is the second option. <span>The solvent will have a higher boiling point.</span>

andriy [413]3 years ago
5 0

Answer:

The correct answer is The solvent will have a higher boiling point

Explanation:

This question will be better understood with the knowledge of colligative property. The colligative properties of a solution are properties that are determined by the concentration of solute in the solution and not the identity of the solute. There are four colligative properties and one of them has been presented in the question.

Consider this common example, when a non-volatile solute like salt is added to a pure solvent like water, the boiling point of the solvent (which is water) becomes increased hence the colligative property here is that, <u><em>the solute causes the elevation/increase in the boiling point of the solvent</em></u>. This is the reason why pure water will boil earlier than an aqueous salt solution (like ocean water).

Thus, from the question, it can be said that when the non-volatile solute is added to the solvent, the solvent will have a higher boiling point.

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For the reaction N2O4(g) ⇋ 2NO2(g), Kc = 0.25 at 98°C. At a point during the reaction, the concentration of N2O4 = 0.50 M and th
Scilla [17]

Answer:

Q = 0.50

No

Left

Explanation:

At a generic reversible equation

aA + bB ⇄ cC + dD

The reaction coefficient (Q) is the ratio of the substances concentrations:

Q = \frac{[C]^c*[D]^d}{[A]^a*[B]^b}

Solids and liquid water are not considered in this calculus.

When the reaction achieves equilibrium (concentrations are constant), the Q value is named as Kc, which is the equilibrium constant of the reaction. If Q > Kc, it indicates that the concentration of the products is higher, so, the reaction must progress to the left and form more reactants; if Q < Kc, than the concentrations of the reactants, are higher, so, the reaction progress to the right.

In this case:

Q = \frac{[NO_2]^2}{[N_2O_4]}

Q = \frac{0.50^2}{0.50}

Q = 0.50

So, Q > Kc, the reaction is not at equilibrium and it progresses to the left.

6 0
3 years ago
Which phrase describes air density?
saw5 [17]

Answer:B equals mass divided by volume

Explanation:I got hacks :)

7 0
3 years ago
Read 2 more answers
A gas that exerts a pressure of ? bar in a container with a volume of 0.5650 L will exert a pressure of 715.1 bar when transferr
uranmaximum [27]
Robert Boyle, the 17th century British chemist, first noticed that the volume of a given amount of gas is inversely proportional to its pressure when kept at a constant temperature. When working with ideal gases we use PV = nRT, but remember n, R, and T are all constant. Therefore we have:

PV(before) = PV(after)

P(0.5650) = (715.1)(1.204)
8 0
3 years ago
Read 2 more answers
A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150
Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

M=\frac{Moles of substance X}{Volume of the solution}

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}

Then you can solve for the volume of the solution:

Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL

Hope it helps!

3 0
4 years ago
QUESTION 10
iris [78.8K]

Answer:

B

Explanation:

Phosphofructokinase-1

6 0
2 years ago
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