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ohaa [14]
3 years ago
14

How does adding a non-volatile solute to a pure solvent affect the boiling point of the pure solvent?

Chemistry
2 answers:
Bogdan [553]3 years ago
7 0

Colligative properties depend on the amount of solute dissolved in a solvent. These set of properties do not depend on the type of species present. These properties include freezing point depression, boiling point elevation, osmotic pressure and vapor pressure lowering. The correct answer is the second option. <span>The solvent will have a higher boiling point.</span>

andriy [413]3 years ago
5 0

Answer:

The correct answer is The solvent will have a higher boiling point

Explanation:

This question will be better understood with the knowledge of colligative property. The colligative properties of a solution are properties that are determined by the concentration of solute in the solution and not the identity of the solute. There are four colligative properties and one of them has been presented in the question.

Consider this common example, when a non-volatile solute like salt is added to a pure solvent like water, the boiling point of the solvent (which is water) becomes increased hence the colligative property here is that, <u><em>the solute causes the elevation/increase in the boiling point of the solvent</em></u>. This is the reason why pure water will boil earlier than an aqueous salt solution (like ocean water).

Thus, from the question, it can be said that when the non-volatile solute is added to the solvent, the solvent will have a higher boiling point.

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A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

                           d = \frac{g}{mL} \\\\ V= \frac{g}{d}  = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L

Now, find moles of CH_{3} OH are needed using the molarity equation:

                           M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH  = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

5 0
3 years ago
To determine the concentration of X in an unknown solution, 1.00 mL of 8.48 mM S was added to 3.00 mL of the unknown X solution
kogti [31]

Answer:

positif

Explanation:

3.87169.843826 = y = x = .ion \: in \: cells = y = x. >  \\  \geqslant  {8}^{2}  \times \frac{4}{3}  | \geqslant |  \times \frac{68.1 < }{3 = 8}

6 0
3 years ago
What’s the compound name for V2(S2O3)3
ohaa [14]

Answer: I HOPE THIS HELPS, HAVE A GREAT EARLY HALLOWEEN

Explanation:

PubChem CID: 1084

Molecular Formula: S2O3(2−) or O3S2-2

Synonyms: Thiosulphate THIOSULFATE ION sulfurothioate UNII-LLT6XV39PY Thiosulfate (S2O32-) More...

Molecular Weight: 112.13 g/mol

7 0
3 years ago
In aqueous solution amino acids are rarely found in the neutral, unionized form.
True [87]

a. True.

There is always an equilibrium of the type

NH₃⁺CHRCOOH ⇌ NH₃⁺CHRCOO⁻ ⇌ NH₂CHRCOO⁻

The compound is <em>always in an ionized form</em>.

There are no unionized NH₂CHRCOOH molecules in the solution.

3 0
3 years ago
When an atom gives off energy in the form of light, a. it becomes excited. b. it becomes more stable. c. it returns to ground st
egoroff_w [7]
Answer is only B.
<span>it becomes more stable</span>

6 0
3 years ago
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