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2 years ago

Which type of matter can be separated by physical means? A. atom B. element C. compound D. mixture

Chemistry

2 answers:

madreJ [45]2 years ago

7 0

Answer:

Explanation:

A pure substance has a constant composition and cannot be separated into simpler substances by physical means. There are two types of pure substances: elements and compounds.

Xelga [282]2 years ago

3 0

Answer:

mixture

Explanation:

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Which of the following indicates the cathode rays has a large charge to mass ratio?

Anna007 [38]

Answer:

Gggg

Explanation:

8 0

2 years ago

How many grams of solute are in 1.00 liter of 0.200m na2so4 solution?

Kisachek [45]

Molarity can be defined as the number of moles of solute in 1 L solution.
Molarity of Na₂SO₄ solution - 0.200 M
this means there are 0.200 moles in 1 L solution
Molar mass of Na₂SO₄ - 142 g/mol
therefore mass of Na₂SO₄ in 1.00 L - 0.200 mol x 142 g/mol = 28.4 g
a mass of 28.4 g of Na₂SO₄ is present in 1.00 L

7 0

3 years ago

A 0.15 m solution of chloroacetic acid has a ph of 1.86. What is the value of ka for this acid?

dem82 [27]

Answer: $1.67\times 10^{-3}$

Explanation:

$ClCH_2COOH\rightarrow ClCH_2COO^-+H^+$

cM 0 0

$c-c\alpha$ $c\alpha$ $c\alpha$

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Given: c = 0.15 M

pH = 1.86

$K_a$ = ?

Putting in the values we get:

Also $pH=-log[H^+]$

$1.86=-log[H^+]$

$[H^+]=0.01$

$[H^+]=c\times \alpha$

$0.01=0.15\times \alpha$

$\alpha=0.06$

As $[H^+]=[ClCH_2COO^-]=0.01$

$K_a=\frac{(0.01)^2}{(0.15-0.15\times 0.06)}$

$K_a=1.67\times 10^{-3]$

Thus the vale of $K_a$ for the acid is $1.67\times 10^{-3}$

4 0

2 years ago

Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen

bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=13mol × 1mol

2mol

x= 13mol

2mol

x= 6.5mol of oxygen

6 0

1 year ago

Give the name of the following molecule. A compound with a total of six carbons with a double bond and the rest single bonds. Th

AlekseyPX

Answer:
The name of given molecule is 3-Methylpent-2-ene.

Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.

Molecule sketched was named as,

1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,

2-Pentene or Pent-2-ene

2) The position of substituent was specified before the parent name, Hence,

3-Methyl-2-Pentene or 3-Methylpent-2-ene

7 0

2 years ago