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KIM [24]
3 years ago
11

What type of energy cause salt to separate from water​

Chemistry
1 answer:
GalinKa [24]3 years ago
3 0

Answer: When you put salt in water, the sodium and chlorine ions separate and attach themselves to individual water molecules. The resulting solution becomes an electrolyte, which means it's capable of conducting electricity.

Explanation:

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Which postulate of Dalton's atomic model was later changed and why?
telo118 [61]

Answer:

Explanation:

Part two of Dalton's theory had to be modified after mass spectrometry experiments demonstrated that atoms of the same element can have different masses because the number of neutrons can vary for different isotopes of the same element. ... Scientists have even developed the technology to see the world on an atomic level!

hoped i helped you :)

4 0
2 years ago
When does the shape of a molecule affect its polarity?
Aliun [14]

Answer:

I think no C

if wrong correct me pls

4 0
3 years ago
Read 2 more answers
Convert the following measurements using dimensional analysis. Set up problem using factors. Cross out the units that cancel. YO
uranmaximum [27]

Answer:

1) 0.423 m

2) 3.107 mi

3) 68.18 kg

4) 0.0083 mem

5) 0.528 gal

6) 4300 mL

7) 32.4 mem

8) 523.013 km

9) 70.866 in

10) 2.3 yek

Note: I can’t type the about equal to sign or the sign that shows a repeating decimal, so check the image for that and my work.

Explanation:

4 0
3 years ago
If 71.5 moles of an ideal gas is at 5.03 atm at 6.80 °C, what is the volume of the gas?
meriva
Use the clapeyron equation:

T in kelvin : 6.80 + 273 => 279.8 K

R = 0.082 

n = 71.5 moles

P = 5.03 atm

Therefore:

P x V = n x R x T

5.03 x V = 71.5 x 0.082 x 279.8

5.03 x V = 1640.4674

V = 1640.4674 / 5.03

V = 326.13 L

hope ths helps!
5 0
3 years ago
A sample of xenon occupies a volume of 736 mL at 2.02 atm and 1 °C. If the volume is changed to 416 mL and the temperature is ch
kozerog [31]

Answer:

\large \boxed{\text{4.63 atm}}

Explanation:

To solve this problem, we can use the Combined Gas Laws:

\dfrac{p_{1}V_{1} }{n_{1}T_{1}} = \dfrac{p_{2}V_{2} }{n_{2}T_{2}}

Data:

p₁ = 2.02 atm; V₁ = 736 mL; n₁ = n₁; T₁ =    1 °C

p₂ = ?;             V₂ = 416 mL; n₂ = n₁; T₂ =  82 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = (   1 + 273.15) K = 274.15 K

T₂ = (82 + 273.15) K = 355.15 K

(b) Calculate the new pressure

\begin{array}{rcl}\dfrac{p_{1}V_{1}}{n_{1} T_{1}} & = & \dfrac{p_{2}V_{2}}{n_{2} T_{2}}\\\\\dfrac{\text{2.02 atm}\times \text{736 mL}}{n _{1}\times \text{274.15 K}} & = &\dfrac{p_{2}\times \text{416 mL}}{n _{1}\times \text{355.15 K}}\\\\\text{5.423 atm} & = &1.171{p_{2}}\\p_{2} & = & \dfrac{\text{5.423 atm}}{1.171}\\\\ & = & \textbf{4.63 atm} \\\end{array}\\\text{The  new pressure will be $\large \boxed{\textbf{4.63 atm}}$}}

6 0
3 years ago
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