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taurus [48]
3 years ago
7

Two lines are parallel if and only if their slopes are equal. Write two if-then statement that are implied by this thesis statem

ent.
Mathematics
1 answer:
Veronika [31]3 years ago
5 0
If and only if (iff) statements are true if only both statements are true of both are false, its double implied.
Here are the implications:
If two lines are parallel then their slopes are equal.
If the slopes of two lines are equal then they are parallel.
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The diameter of the larger circle is 12.5 cm.
notsponge [240]
If the diameter of the smaller circle is 3.5cm, that means the radius is 1.75cm.The area of the smaller circle is π × 1.75², which is ≈ 9.62112750162. 
The diameter of the larger circle is 12.5 cm, so the radius would be half that, which is 6.25cm. The area of the larger circle would be π × 6.25², which is ≈ 122.718463031.
So now that we know the area of the larger circle and the smaller circle, we can find the area of the shaded region by subtracting the area of the smaller circle from the area of the larger circle, which is basically just 122.718463031 - 9.62112750162, which is = 113.097336. The closest answer here is 113.04, hence the answer is 113.04cm². 
 
6 0
3 years ago
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Help me plz I have headache and cant think
Alenkasestr [34]

Answer: y=9

Step-by-step explanation:

Simplifying

7y = 3y + 36

Reorder the terms:

7y = 36 + 3y

Solving

7y = 36 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.

7y + -3y = 36 + 3y + -3y

Combine like terms: 7y + -3y = 4y

4y = 36 + 3y + -3y

Combine like terms: 3y + -3y = 0

4y = 36 + 0

4y = 36

Divide each side by '4'.

y = 9

Simplifying

y = 9

5 0
3 years ago
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The perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions.
Vanyuwa [196]

Answer:

20 m by 10 m

Step-by-step explanation:

let w be width and l be length , then

2(l + w) = 60 ( divide both sides by 2 )

l + w = 30 ( subtract w from both sides )

l = 30 - w → (1)

lw = 200 → (2)

Substitute l = 30 - w into (2)

w(30 - w) = 200 ← distribute parenthesis on left side

30w - w² = 200 ( subtract 200 from both sides )

30w - w² - 200 = 0 ( multiply through by - 1 )

w² - 30w + 200 = 0 ← in standard form

(w - 10)(w - 20) = 0 ← in factored form

Equate each factor to zero and solve for w

w - 10 = 0 ⇒ w = 10

w - 20 = 0 ⇒ w = 20

Substitute these values into (1)

l = 30 - 10 = 20

l = 30 - 20 = 10

dimensions of field is 20 m by 10 m

4 0
2 years ago
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Which situation CANNOT be represented by this equation?
fomenos
The second one, because the price of the candle is $4, meaning the equation would have to be 4x+3=19
8 0
3 years ago
Can someone help me? It's urgent and thank you!
Irina-Kira [14]

Answer:

option A

Step-by-step explanation:

\frac{x+ 3}{12x} \ \cdot \ \frac{4x}{x^2 +x - 6}\\\\= \frac{x+ 3}{12x} \ \cdot\ \frac{4x}{x^2 +3x - 2x - 6}\\\\= \frac{x+ 3}{12x} \cdot \frac{4x}{x(x + 3) -2(x+3)}\\\\= \frac{x+ 3}{12x} \cdot \frac{4x}{(x + 3)(x -2)}\\\\= \frac{1}{12x} \ \cdot \ \frac{4x}{(x - 2)} \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \  \\\\= \frac{1}{3} \ \cdot \ \frac{1}{(x - 2)}\\\\= \frac{1}{3(x - 2) }

5 0
3 years ago
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