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Eddi Din [679]
3 years ago
13

write the symbols for the ions that form when potassium and iodine react to form the ionic compound potassium iodide.

Chemistry
2 answers:
irakobra [83]3 years ago
5 0

Answer:

I^{-}

K^{+}

Explanation:

As iodine has a higher electronegativity value and 7 valence electrons, it takes the valence electron of potassium to complete 8 electrons in its valence shell thus forming the anion I^{-} and, as consequence of losing one electron, the K atoms forms the cation K^{+}

The formula of potassium iodide is KI

Bingel [31]3 years ago
3 0
I believe it isK+  + I-=KI
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Answer:

M = 0.050 M

Explanation:

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HCl + NaOH -------> NaCl + H₂O

As we can see, we have a balanced equation already, and we can also see that the mole ratio between the HCl and NaOH is 1:1, therefore we can use the following expression:

M₁V₁ = M₂V₂       1: acid;   2: base

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5 0
3 years ago
Please show all work:
Tom [10]

If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

Mg + 2HNO₃  → Mg(NO₃)₂ + H₂

According to Stoichiometry

40.9\ \text{g Mg} \times \frac{1\ \text{mol Mg}}{24.31\ \text{g Mg}} \times \frac{1\ \text{mol}\ H_2}{1\ \text{mol Mg}} \times \frac{2.02\ g\ H_2}{1\ \text{mol}\ H_2}

= 3.3 g H₂

Thus from the above conclusion we can say that If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

Learn more about the Stoichiometry here: brainly.com/question/16060223

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