1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vesna_86 [32]
4 years ago
13

Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. fo

r example, [he]2s22p2should be entered as [he]2s^22p^2.
Chemistry
1 answer:
alex41 [277]4 years ago
4 0
There are 6 elements that are given and these are:Nickel, Selenium, Cadmium, Uranium, Lead, and Cesium. These are their condensed electronic configuration.
Ni – [Ar] 4s2 3d8Se – [Ar] 4s2 3d10 4p4Cd – [Kr] 5s2 4d10U – [Rn] 7s2 5f4Pb – [Xe] 6s2 4f14 5d10 6p2CS – [Xe] 6s1
You might be interested in
Atoms and molecules are constantly in motion. The more energy the atom or molecule contains, the faster they move about. In whic
Rus_ich [418]

Answer:

Solid

Explanation:

5 0
2 years ago
Please help!!!!!! I need this question answered
salantis [7]
The answer would be A) cells!!
5 0
3 years ago
Read 2 more answers
A mixture of methanol and methyl acetate contains 15.0 wt% methanol.
Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h

5 0
3 years ago
Convert 533 cm/s to units of meters per minute. Show the unit analysis by dragging the conversion factors into the unit‑factor s
lukranit [14]

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

8 0
3 years ago
At sea level, a kilogram welghs approximately<br> 2 pounds<br> 10 pounds<br> 5 pounds<br> 1 pound
Vedmedyk [2.9K]

Answer:

1 kilogram weight at sea level would be the equivalent of  2 pounds.

Explanation:

5 0
3 years ago
Other questions:
  • Draw the most reasonable lewis structure of a molecule that contains a n atom, a c atom, and a h atom. include any formal charge
    13·1 answer
  • Write a balanced net ionic equation for the reaction of aqueous solutions of baking soda (NaHCO3) and acetic acid.(A) HCO3–(aq)
    15·1 answer
  • The reaction described in part a required 3.35 l of calcium chloride. what is the concentration of this calcium chloride solutio
    10·1 answer
  • Someone please help me , number 14
    13·1 answer
  • How do weathering and deposition differ? (4 points)
    5·1 answer
  • A 20.0-milliliter sample of 0.200 M K2CO3 solution is added to 30.0 milliliters of 0.400 M Ba(NO3)2 solution.
    5·1 answer
  • ir masses that originate in the Gulf of Mexico A. continental tropical B. maritime tropical C. maritime polar D. continental pol
    7·1 answer
  • If 0.400 moles CO and 0.400 moles O2 completely react how many grams of CO2 are produces?
    5·1 answer
  • How many molecules are in 21.5G of water
    10·1 answer
  • What can the shape of a molecule affect?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!