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vesna_86 [32]
3 years ago
13

Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. fo

r example, [he]2s22p2should be entered as [he]2s^22p^2.
Chemistry
1 answer:
alex41 [277]3 years ago
4 0
There are 6 elements that are given and these are:Nickel, Selenium, Cadmium, Uranium, Lead, and Cesium. These are their condensed electronic configuration.
Ni – [Ar] 4s2 3d8Se – [Ar] 4s2 3d10 4p4Cd – [Kr] 5s2 4d10U – [Rn] 7s2 5f4Pb – [Xe] 6s2 4f14 5d10 6p2CS – [Xe] 6s1
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3 years ago
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A sample of gas occupies a volume of 350.0 mL at 840mm Hg and 33°C. Determine the volume of this sample at 600 mm By and 52°C​
insens350 [35]

Answer:

V₂ = 520.42 mL

Explanation:

Given data:

Initial volume = 350.0 mL

Initial pressure = 840 mmHg

Initial temperature = 33°C (33 +273 = 306 K)

Final temperature = 52°C (52+273 = 325 K)

Final volume = ?

Final pressure = 600 mmHg

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 840 mmHg × 350.0 mL × 325 K / 306 K × 600 mmHg

V₂ = 95550000 mmHg.mL.K /183600 K.mmHg

V₂ = 520.42 mL

7 0
2 years ago
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