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vesna_86 [32]
3 years ago
13

Express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. fo

r example, [he]2s22p2should be entered as [he]2s^22p^2.
Chemistry
1 answer:
alex41 [277]3 years ago
4 0
There are 6 elements that are given and these are:Nickel, Selenium, Cadmium, Uranium, Lead, and Cesium. These are their condensed electronic configuration.
Ni – [Ar] 4s2 3d8Se – [Ar] 4s2 3d10 4p4Cd – [Kr] 5s2 4d10U – [Rn] 7s2 5f4Pb – [Xe] 6s2 4f14 5d10 6p2CS – [Xe] 6s1
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The name of the ion P3- is phosphoride ion.<br><br> True<br> False
melisa1 [442]
I believe that it would be false. <span>The name of the ion P3- is not phosphoride ion but it is phosphide ion. </span><span>The </span>phosphide ion<span> is P </span>3−<span>, and </span>phosphides<span> of almost every metal in the periodic table are known. They exhibit a wide variety of chemical and physical properties. Hope this answers the question.</span>
5 0
3 years ago
What happens when Potassium Hydroxide reacts with Sulphuric Acid?​
Ede4ka [16]

As we know that neutralization reaction is a reaction in which base react with acid to form salt and water.

When Potassium Hydroxide reacts with Sulphuric Acid, it forms Potassium Sulphate and Water.

As a result of neutralization reaction, Potassium Sulphate and Water is formed.

2KOH + H2SO4 ----> K2SO4 + 2H2O

Here, K2SO4 is found in aqueous medium in neutralization reaction. It is a neutral salt.

5 0
3 years ago
Read 2 more answers
For elements (Br, Ca, Fe, Na, S, Si, and Xe) which of the following term(s) apply?
ioda

Answer:

Detail is given below.

Explanation:

Bromine: Br (Halogen and non metal)

Bromine is present in group 17 and it is called halogen.

All halogens are very reactive.

Calcium; Ca ( alkaline earth metal)

Calcium is present in group 2. It is alkaline earth metal.

It has two valance electrons.

Iron; Fe (Transition metal)

Iron is transition metal and also called d-block element.

Sodium: Na (Metal, main group element)

Sodium is metal and present in group one.

It has one valance electron.

Sulfur: S (non metal)

Sulfur is non metal. It is present in group 16.

It has six valance electrons.

Silicon: Si (metalloid)

Silicon is metalloid. It is present in group 14.

It has four valance electrons.

Xenon: Xe (Noble gas, gas at a room temperature)

it is noble gas. Xenon is present in group 18.

It is gas at a room temperature.

3 0
3 years ago
A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num
-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}

<em>B) Radius</em>

\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}

V = \frac{ 4}{3 }\pi r^{3}

r^{3} = \frac{3V }{4 \pi }\

r= \sqrt [3]{ \frac{3V }{4 \pi } }

r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}

3 0
3 years ago
There is water on the pan of the scale as you measure the mass of an object. If you were to ignore the water, what would be the
mihalych1998 [28]
Remember that density refers to the "mass per unit volume" of an object.

So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.

In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is

As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:

density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml

The effect on density would be that it would erroneously appear to be greater

Hope this helps!

Good luck
6 0
3 years ago
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