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3 years ago

Help on science please!

Chemistry

1 answer:

erik [133]3 years ago

6 0

Answer:

See explanation.

Explanation:

1. Forrest: From 425,000,000 to 300,000,000 is a change of 125,000,000. Divide the 125,000,000 by 425,000,000 to get the percent change:

125,000,000 / 425,000,000 = .294, which is a 29.4% change, a decrease.

2. Population: From 4,500 to 326,500,000 is a change of 326,495,500. Divide 326,495,500 by 4,500 to get the percent change.

326,495,500 / 4,500 = 72,554.55 which is a change of 7,255,455% change, an increase.

3. Conclusion: The growth in population required living area. People needed farms, houses, cities, and communities to live in. Forests were cleared to make room for the people to live. Forests are also used to provide building materials. The population increase contributed to the decrease in forest lands.

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The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that

kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is $1.1\times 10^6$ M.

$HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)$

This value indicates that

A. $CN^-$ is a stronger base than $ONO^-$

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is $ONO^-$

D. The conjugate acid of CN- is HCN

Answer: A. $CN^-$ is a stronger base than $ONO^-$

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When $K_{p}>1$ ; the reaction is product favoured.

When $K_{p};$ ; the reaction is reactant favored.

$When K_{p}=1$ ; the reaction is in equilibrium.

As, $K_p>>1$ , the reaction will be product favoured and as it is a acid base reaction where $HONO$ acts as acid by donating $H^+$ ions and $CN^-$ acts as base by accepting $H^+$

Thus $HONO$ is a strong acid thus $ONO^-$ will be a weak conjugate base and $CN^-$ is a strong base which has weak $HCN$ conjugate acid.

Thus the high value of K indicates that $CN^-$ is a stronger base than $ONO^-$

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