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Kruka [31]
3 years ago
6

One method for preparing pure iron from Fe2O3 is by reaction with carbon monoxide.Fe2O3(s)+CO(g)→Fe(s)+CO2(g) How many moles of

carbon monoxide are needed to react completely with 122 kg of Fe2O3.
Chemistry
1 answer:
larisa [96]3 years ago
6 0

Answer:

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

Explanation:

Given data:

Mass of Fe₂O₃ = 122 Kg ( 122×1000 =  122000 g)

Moles of CO = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO  → 2Fe + 3CO₂

Number of moles of  Fe₂O₃:

Number of moles = mass/ molar mass

Number of moles = 122000 g /159.69 g/mol

Number of moles = 764 mol

Now we will compare the moles of Fe₂O₃ with CO.

                               Fe₂O₃            :            CO  

                                  1                  :             3

                               764                :             3×764  =2292 mol

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

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If an ice cube weighing 25.0 g with an initial
riadik2000 [5.3K]

Answer:

11

∘

C

Explanation:

As far as solving this problem goes, it is very important that you do not forget to account for the phase change underwent by the solid water at

0

∘

C

to liquid at

0

∘

C

.

The heat needed to melt the solid at its melting point will come from the warmer water sample. This means that you have

q

1

+

q

2

=

−

q

3

(

1

)

, where

q

1

- the heat absorbed by the solid at

0

∘

C

q

2

- the heat absorbed by the liquid at

0

∘

C

q

3

- the heat lost by the warmer water sample

The two equations that you will use are

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of water, equal to

4.18

J

g

∘

C

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

and

q

=

n

⋅

Δ

H

fus

, where

q

- heat absorbed

n

- the number of moles of water

Δ

H

fus

- the molar heat of fusion of water, equal to

6.01 kJ/mol

Use water's molar mass to find how many moles of water you have in the

100.0-g

sample

100.0

g

⋅

1 mole H

2

O

18.015

g

=

5.551 moles H

2

O

So, how much heat is needed to allow the sample to go from solid at

0

∘

C

to liquid at

0

∘

C

?

q

1

=

5.551

moles

⋅

6.01

kJ

mole

=

33.36 kJ

This means that equation

(

1

)

becomes

33.36 kJ

+

q

2

=

−

q

3

The minus sign for

q

3

is used because heat lost carries a negative sign.

So, if

T

f

is the final temperature of the water, you can say that

33.36 kJ

+

m

sample

⋅

c

⋅

Δ

T

sample

=

−

m

water

⋅

c

⋅

Δ

T

water

More specifically, you have

33.36 kJ

+

100.0

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

0

)

∘

C

=

−

650

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

25

)

∘

C

33.36 kJ

+

418 J

⋅

(

T

f

−

0

)

=

−

2717 J

⋅

(

T

f

−

25

)

Convert the joules to kilojoules to get

33.36

kJ

+

0.418

kJ

⋅

T

f

=

−

2.717

kJ

⋅

(

T

f

−

25

)

This is equivalent to

0.418

⋅

T

f

+

2.717

⋅

T

f

=

67.925

−

33.36

T

f

=

34.565

0.418

+

2.717

=

11.026

∘

C

Rounded to two sig figs, the number of sig figs you have for the mass of warmer water, the answer will be

T

f

=

11

∘

C

Explanation:

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How many kilograms of potassium iodide (ki) are needed to make 1.25 l of a 4.41 m ki solution?
Lapatulllka [165]
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n = C×V
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vova2212 [387]

Answer:

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