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Kruka [31]
3 years ago
6

One method for preparing pure iron from Fe2O3 is by reaction with carbon monoxide.Fe2O3(s)+CO(g)→Fe(s)+CO2(g) How many moles of

carbon monoxide are needed to react completely with 122 kg of Fe2O3.
Chemistry
1 answer:
larisa [96]3 years ago
6 0

Answer:

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

Explanation:

Given data:

Mass of Fe₂O₃ = 122 Kg ( 122×1000 =  122000 g)

Moles of CO = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO  → 2Fe + 3CO₂

Number of moles of  Fe₂O₃:

Number of moles = mass/ molar mass

Number of moles = 122000 g /159.69 g/mol

Number of moles = 764 mol

Now we will compare the moles of Fe₂O₃ with CO.

                               Fe₂O₃            :            CO  

                                  1                  :             3

                               764                :             3×764  =2292 mol

The 2292 moles of CO are needed to react completely with 122 Kg of Fe₂O₃.

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A 2.50-l volume of hydrogen measured at â196 °c is warmed to 100 °c. calculate the volume of the gas at the higher temperature
ivann1987 [24]

To solve this we assume that the hydrogen gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = (100 + 273.15) K x 2.50 L / (-196 + 273.15) K

<span>V2 = 12.09 L</span>

Therefore, the volume would increase to 12.09 L as the temperature is increased to 100 degrees Celsius.

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5 0
3 years ago
Which of the following causes a physical change in the shape of an object?
babunello [35]

Answer:

B

Explanation:

Heating a piece of iron until it glows.

3 0
2 years ago
Three fundamental types of organic molecules are proteins, carbohydrates, and lipids. What is the fourth type?
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Read 2 more answers
Use mathematics to prove that the 5.50 grams of salicylic acid (C7H6O3) used in this experiment is equal to 0.04 mol.
g100num [7]

Answer:

Please find the answer to the question below

Explanation:

In chemistry, the following mathematical formula is used to calculate the number of moles contained by a substance:

mole = mass of substance (g)/molar mass of substance (g/mol)

Molar mass of salicylic acid (C7H6O3) = 12(7) + 1(6) + 16(3)

= 84 + 6 + 48

= 138g/mol

Mass = 5.50grams

mole = 5.5/138

mole = 0.039

Approximately, the number of moles of 5.5grams of salicylic acid is 0.04moles. This is in accordance with the mole value (0.04) given in this question.

7 0
3 years ago
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
3 years ago
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