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barxatty [35]
3 years ago
7

Word equation for Silver being added to sulphuric acid

Chemistry
1 answer:
zhenek [66]3 years ago
7 0

Answer:

See the answer below

Explanation:

<em>When silver is added to dilute sulphuric acid, no reaction would occur. However, silver reacts with hot and concentrated sulphuric acid to produce silver sulphate, sulphur dioxide, and water.</em>

The equation of the reaction is as below:

silver + sulphuric acid --> silver sulphate + water + sulphur dioxide

2Ag(s) + 2 H_2SO_4(aq) -->Ag_2SO_4 (s) + 2 H_2O (l) + SO_2 (aq)

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When a solution of NaI reacts with a solution of AgNO3, what is the net ionic equation?
Leni [432]

Answer:

Ag⁺(aq) + I⁻(aq) → AgI(s)

Explanation:

Net ionic equation is a way to write a chemical equation in which you are listing only the species that are participating in the reaction.

In the reaction:

AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq).

The ionic equation is:

Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + I⁻(aq) → AgI(s) + Na⁺(aq) + NO₃⁻(aq).

Now, listing only the species that are participating in the reaction:

<h3>Ag⁺(aq) + I⁻(aq) → AgI(s)</h3>

3 0
4 years ago
Why did the water turn blue after the food coloring was added to the water
o-na [289]
Because when mixed the food coloring spreads to the less dense parts of the water cup. 
8 0
3 years ago
Containment of radioactive isotopes is accomplished by storing them in deep tanks of _____
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Answer:

short-lived radioisotopes in ... It will be the first deep geological repository licenced for the disposal

Explanation:

8 0
3 years ago
An ore sample is known to contain copper sulfate pentahydrate, CuSO4•5H2O. If a 10.000 g sample of the ore loses 0.8445 g of wat
Simora [160]

Answer:

2,341g of CuSO₄.5H₂O

Explanation:

It is possible to assume all loses water comes from CuSO₄.5H₂O. Thus:

0,8445g H₂O (1mol H₂O / 18,015g) = 0,04688 moles of water.

As 1 mole of contains 5 moles of water, moles of CuSO₄.5H₂O are:

0,04688 moles H₂O × (1 mole CuSO₄.5H₂O / 5 moles H₂O) = 9,38x10⁻³ moles of CuSO₄.5H₂O

The molecular mass of CuSO₄.5H₂O is 249,69g/mol. Thus, mass of 9,38x10⁻³ moles of CuSO₄.5H₂O is:

9,38x10⁻³ moles of CuSO₄.5H₂O × (249,69g / mol) =

<em>2,341g of CuSO₄.5H₂O </em>is the maximum quantity of CuSO₄.5H₂O that could be in the sample.

I hope it helps!

3 0
3 years ago
What is the net ionic equation resulting from a reaction of aqueous solutions of nitric acid and sodium hydroxide?
dsp73

Answer:

equals ABC

Explanation:

4 0
3 years ago
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