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barxatty [35]
3 years ago
7

Word equation for Silver being added to sulphuric acid

Chemistry
1 answer:
zhenek [66]3 years ago
7 0

Answer:

See the answer below

Explanation:

<em>When silver is added to dilute sulphuric acid, no reaction would occur. However, silver reacts with hot and concentrated sulphuric acid to produce silver sulphate, sulphur dioxide, and water.</em>

The equation of the reaction is as below:

silver + sulphuric acid --> silver sulphate + water + sulphur dioxide

2Ag(s) + 2 H_2SO_4(aq) -->Ag_2SO_4 (s) + 2 H_2O (l) + SO_2 (aq)

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23 grams of sodium reacts with 293 cm 3 of water that is initially at 298 K. It produces an enthalpy change of 197 kJ. What is t
muminat

Answer:

THE FINAL TEMPERATURE OF WATER IS 459.32 K

Explanation:

Mass of sodium = 23 g

Volume of water = 293 cm3

Initial temperature = 298 K

Specific heat capacity of water = 4.18 J/Kg

Enthalpy change = 197 kJ = 197, 000 J

Heat  = mass * specific heat * change in temperature

From the statement it shows that the initial temperature is 298 K or 25 °C and at this temperature the density of water is 0.99707 g/mL

Hence we can calculate the mass of water by using this formula:

Mass = volume * density

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Mass = 292.14 g

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197, 000 = 292.14 * 4.18 * change in temperature

Change in temperature = 197 000 / 292.14 * 4.18

Change in temperature = 197 000 / 1221.1452

Change in temperature = 161.32 K

Hence, the final temperature of the water is therefore the addition of initial temperature and the change in temperature

Final temperature = initial temp + change in temp

Final temp = 298 K + 161.32 K

Final temp = 459.32 K

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