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mina [271]
3 years ago
6

A cone's height is equal to the radius of its base. The area of its base is 1,386 square units. The approximate radius of the co

ne's base is____ units. The approximate volume of the cone is ____cubic units. Use . Pie= 22/7
Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer:

  • 21 units
  • 9702 units³

Step-by-step explanation:

The area of the base is given by the formula ...

  A = πr²

so the radius is ...

  r = √(A/π) = √(1386/(22/7)) = √441 = 21 . . . units

__

The volume is given by ...

  V = (1/3)Bh

where B is the area of the base, and h is the height (equal to the radius). Filling in the numbers, we have ...

  V = (1/3)(1386)(21) = 9702 . . . . cubic units

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a group of students went hiking in wildlife sanctuary. during the hike a total of 180 ticks and mosquitoes were slapped. if thes
SVEN [57.7K]

Answer:

m = 100, t = 80

Step-by-step explanation:

m +  t = 180

6m + 8t = 1240

3 0
2 years ago
Jason has 60 toy cars 30% of the cars are blue how many cars are blue?<br><br> Please Show Work!!
Temka [501]

Answer:

18

Step-by-step explanation:

30%=.3

60*.3=18

30% of 60 =18

5 0
3 years ago
What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37​
bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\

Step-by-step explanation:

\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}

\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\

\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}

6 0
2 years ago
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A plant that manufactures metal plates has a quality control team to check that the plates are the right size. A rectangular pla
Kamila [148]

Answer:

Given the size of rectangular plate in advertisement = 5 cm by 3cm.

Given the condition for length should be   = 0.25 of 5 cm  

Step-by-step explanation:

Now, have to write the inequality from the given data.

Therefore,  5- 0.25 ≤ L ≤ 5+.25

4.75 ≤ L ≤ 5.25

We know that the area of a rectangle =  Length × Width.

 Width = 3

Thus, the area is 3 × L

3× (4.75) ≤ 3×L ≤3× (5.25)

14.25 ≤ 3×L ≤ 15.75

So the minimum area is 14.25 cm^2

The maximum area is 15.75 cm^2

4 0
2 years ago
Knowledge, intensify, skills and grow net work​
frosja888 [35]

Answer:

u nice keep goin.

sry lol

4 0
3 years ago
Read 2 more answers
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