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faust18 [17]
3 years ago
10

Use standard reduction potentials to find the equilibrium constant for the following reaction at 25°C: 2Ce4+(aq) + 2Cl−(aq) ⇌ 2C

e3+(aq) + Cl2(g) Enter your answer in scientific notation to one significant digit.

Chemistry
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

The equilibrium constant for the following reaction = 501.18

Explanation:

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How many moles of oxygen are present in 33.6l of the gas at 1atm and 0c
andreev551 [17]

The answer is: 1.5 moles of oxygen are present.

V(O₂) = 33.6 L; volume of oxygen.

p(O₂) = 1.0 atm; pressure of oxygen.

T = 0°C; temperature.

Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

At STP one mole of gas occupies 22.4 liters of volume.

n(O₂) = V(O₂) ÷ Vm.

n(O₂) = 33.6 L ÷ 22.4 L/mol.

n(O₂) = 1.50 mol; amount of oxygen.

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3 years ago
This reaction type occurs when different atoms in two different compounds trade places.
Scorpion4ik [409]
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Setler79 [48]

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5 0
2 years ago
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Which elements have the quantum numbers (4,3,-2,+1/2) and (5,2,-1,-1/2)
nikklg [1K]

The elements are samarium (Sm) and silver (Ag).  

<em>Quantum numbers (4,3,-2,+½)  </em>

<em>n</em> = 4: Principal quantum number = 4.  

<em>l</em> = 3: Element has 4f electrons  

It is <em>conventional</em> to list quantum numbers in decreasing order.  

<em>Hund’s rule </em>states that all the orbitals must be half-filled with electrons having the same spin before any can receive a second electron.  

We get the following table:  

<u>Element </u><em><u>n</u></em><u> </u><em><u>l</u></em><u>   </u><em><u>m</u></em><u>ₗ </u><em><u>m</u></em><u>ₛ</u>  

    La      4 3   3 +½  

    Ce     4 3   2 +½  

    Pr      4 3   1  +½  

    Nd    4 3   0 +½  

    Pm   4 3  -1   +½  

    Sm   4 3 -2 +½  

The element is samarium, Sm.  

<em>Quantum numbers (5,2,-1,-½)  </em>

<em>n</em> = 5: Principal quantum number = 5.  

<em>l</em> = 2: Element has <em>5d</em> electrons  

We get the following table:  

<u>Element </u><em><u>n</u></em><u>  </u><em><u>l m</u></em><u>ₗ mₛ</u><em><u>  </u></em>

<em>  </em>   Y       5<em> </em>2  2 +½  

    Zr      5 2  1 +½  

    Nb    5 2  0 +½  

    Mo   5 2  -1 +½  

    Tc    5 2  -2 +½  

    Ru   5 2   2  -½  

    Rh   5 2   1   -½  

    Pd   5 2   0  -½  

    Ag   5 2  -1  -½  

The element is silver, Ag.

<em>Note</em>: These assignments assume that there are <em>no exceptions</em> in the Periodic Table.

7 0
3 years ago
How many grams of water can I convert from a liquid to a gas with 6768 joules?
vredina [299]

Answer:

The amount of water converted from liquid to gas with 6,768 joules is approximately 3.035 g

Explanation:

The amount of heat required to convert a given amount of liquid to gas at its boiling point is known as the latent heat of evaporation of the liquid

The latent heat of evaporation of water, ΔH_v ≈ 2,230 J/g

The relationship between the heat supplied, 'Q', and the amount of water in grams, 'm', evaporated is given as follows

Q = m × ΔH_v

Therefore, the amount of water, 'm', converted from liquid to gas at the boiling point temperature (100°C), when Q = 6,768 Joules, is given as follows;

6,768 J = m × 2,230 J/g

∴ m = 6,768 J /(2,230 J/g) ≈ 3.035 g

The amount of water converted from liquid to gas with 6,768 joules = m ≈ 3.035 g.

8 0
3 years ago
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