Answer: 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.
Justification:
Althought the question is too open, other answers may arise, the most remarkable similarity between the two compounds is that both are diatomic.
That means that both molecules oxygen, O₂, and carbon monoxide, CO have two atoms.
So, 1 mol of oxygen, O₂, and 1 mol of CO will have the same number of molecules, and the same number of atoms.
You must remember that 1 mol means a specific number. It is Avogadro's number, which is 6.022 × 10 ²³.
So 1 mol of CO and 1 mol of O₂ are the same number of representative particles: 6.022 ×10²³ molecules eac, and two times that number of atoms each (since each molecule has two atoms).
Answer:
The answer is:
(a)
(b) NaCl
(c) 0.211 g
Explanation:
Given:
The mass of NaCl,
= 0.0860 g
The molar mass of NaCl,
= 58.44 g/mol
The volume of ,
= 30.0 ml
or,
= 0.030 L
Molarity of ,
= 0.050 M
Moles of NaCl will be:
=
=
=
now,
Moles of will be:
(a)
The reaction is:
⇒
(b)
1 mole of NaCl react with,
= 1 mol of
0.0015 mol needs,
=
Available mol of NaCl < needed amount of NaCl
So,
The limiting reagent is "NaCl".
(c)
The precipitate formed,
=
=
<span>((P1V1/T1)=(P2V2/T2))</span>
Your answer is option b
i.e. Red
because refractive index of red is more as compared to green, yellow and violet...