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givi [52]
3 years ago
14

This unit describes volume, and may be used to describe liquids or gases.

Chemistry
2 answers:
Trava [24]3 years ago
5 0
A. Meter is the answer
SSSSS [86.1K]3 years ago
3 0

Answer:   aaaaaaaaaaa

The basic SI unit for volume is the cubic meter (m3), but smaller volumes may be measured in cm3, and liquids may be measured in liters (L) or milliliters (mL).

Explanation:

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Why is the Law of Conservation of Mass a law, rather than a theory?
Colt1911 [192]

Answer: During a chemical reaction, matter cannot be created nor destroyed, matter can change form through physical and chemical changes, but through any of these changes, matter is conserved; even though the matter may change from one form to another, the same number of atoms exists before and after the change takes place.

Explanation: <3

8 0
3 years ago
Determine the mass in grams of each element.
jeka57 [31]

1. The mass of 1.33×10²² mole of Sb is 1.62×10²⁴ g

2. The mass of 4.75×10¹⁴ mole of Pt is 9.26×10¹⁶ g

3. The mass of 1.22×10²³ mole of Ag is 1.32×10²⁵ g

4. The mass of 9.85×10²⁴ mole of Cr is 5.12×10²⁶ g

<h3>1. Determination of the mass of 1.33×10²² mole of Sb</h3>
  • Mole of Sb = 1.33×10²² mole
  • Molar mass of Sb = 122 g/mol
  • Mass of Sb =?

Mass = mole × molar mass

Mass of Sb = 1.33×10²² × 122

Mass of Sb = 1.62×10²⁴ g

<h3>2. Determination of the mass of 4.75×10¹⁴ mole of Pt</h3>
  • Mole of Pt = 4.75×10¹⁴ mole
  • Molar mass of Pt = 122 g/mol
  • Mass of Pt =?

Mass = mole × molar mass

Mass of Pt = 4.75×10¹⁴ × 195

Mass of Pt = 9.26×10¹⁶ g

<h3>3. Determination of the mass of 1.22×10²³ mole of Ag</h3>
  • Mole of Ag = 1.22×10²³ mole
  • Molar mass of Ag = 108 g/mol
  • Mass of Ag =?

Mass = mole × molar mass

Mass of Ag = 1.22×10²³ × 108

Mass of Ag = 1.32×10²⁵ g

<h3>4. Determination of the mass of 9.85×10²⁴ mole of Cr</h3>
  • Mole of Cr = 9.85×10²⁴ mole
  • Molar mass of Cr = 52 g/mol
  • Mass of Cr =?

Mass = mole × molar mass

Mass of Cr = 9.85×10²⁴ × 52

Mass of Cr = 5.12×10²⁶ g

Learn more about mole:

brainly.com/question/13314627

7 0
2 years ago
A 56.8g sample of aluminum is heated from 79.5°C to 143.7°C. The specific heat capacity of aluminum is 0.900 J/(g*K). Calculate
Mashutka [201]

Answer:

I think the answer is A.

4 0
4 years ago
If the formula for potassium chlorate is KClO3 and the formula for magnesium fluoride is MgF2, then what isthe formula for magne
mr_godi [17]
The formula for magnesium chlorate is Mg(ClO3)2.
5 0
3 years ago
balance the following equation by oxidation number method KMnO4 + Na2So3 gives Mno2 + Na2 So4 + Koh​
belka [17]

Answer:

good i think

Explanation:

yes correct

7 0
3 years ago
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