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navik [9.2K]
3 years ago
8

Does the following infinite series converge or diverge? Explain your answer. 1/2 - 2/9 + 4/27 - 8/81

Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0
Something tells me the first term is supposed to be \dfrac13, not \dfrac12. In that case, the series would be

\displaystyle\sum_{n=0}^\infty\frac{(-2)^n}{3^{n+1}}=\frac13\sum_{n=0}^\infty\left(-\frac23\right)^n

which is geometric with a ratio less than 1, so the infinite series will converge, and moreover will converge to

\dfrac13\cdot\dfrac1{1+\frac23}=\dfrac15

Even if the first term was \dfrac12, the series will still converge, but we can't write it as we did above. Not counting the first term, we still have a convergent geometric series.
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Write an equation that defines the function :)
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see below

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A carpet remnant is shaped like a triangle. It has a height of 32 inches and a base of 8 inches. Write an equation to represent
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128 square inches.



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4 0
3 years ago
Read 2 more answers
10.045+2.673+105.95 to the nearest whole number and then estimate the sum
horsena [70]

Answer:

119

Step-by-step explanation:

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5 0
3 years ago
What equation represents y=2x^2+24x+85 in vertex form
Andrej [43]
Y=a(x-h)^2+k

vertex form is basically completing the square

what you do is
for
y=ax^2+bx+c
1. isolate x terms
y=(ax^2+bx)+c
undistribute a
y=a(x^2+(b/a)x)+c
complete the square by take 1/2 of b/a and squaring it then adding negative and postive inside
y=a(x^2+(b/a)x+(b^2)/(4a^2)-(b^2)/(4a^2))+c
complete square
too messy \
anyway

y=2x^2+24x+85
isolate
y=(2x^2+24x)+85
undistribute
y=2(x^2+12x)+85
1/2 of 12 is 6, 6^2=36
add neagtive and postivie isnde
y=2(x^2+12x+36-36)+85
complete perfect square
y=2((x+6)^2-36)+85
distribute
y=2(x+6)^2-72+85
y=2(x+6)^2+13

vertex form is
y=2(x+6)^2+13
8 0
3 years ago
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