3 years ago

What is the mass of 5.30×1021 platinum atoms?

1 answer:

3 0

<span>(5.08 * 10^21) / (6.022 * 10^23) = 0.0084357 moles * 195.084 g/mol = 1.65 g Atomic mass of platinum = 195.084 g/mol Avogadro's number = 6.022 * 10^23 so here you go</span>

You might be interested in

Which of the following is the smallest volume? 500 mL 2,500 cm3 5.5 x 10-1 L 25 m3

Anni [7]

500 ml is the answer

6 0

3 years ago

Two students made the Lewis dot diagrams of H2O. The diagrams are as shown.

netineya [11]

Answer:

Only student A

Explanation:

don’t worry I got a 100

7 0

3 years ago

Read 2 more answers

The solubility of nacl at 30°c is 36.3 g/100 g of water. what mass of nacl is contained in a saturated solution that contains 30

sleet_krkn [62]

Because a solubility is calculated for saturated solutions we can write:

36.3 g NaCl ---100g water
x g NaCl ---- 300.0 g water

x=36.3*300/100=108.9 g NaCl

7 0

3 years ago

Read 2 more answers

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 3.50 moles of magnesium

Firdavs [7]

Answer:

$n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO$

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

$n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO$

Best regards!

3 0

2 years ago

The 54.9-g sample of the compound X2O7 contains 33.6 g of oxygen atoms. What is the molar mass of element X?

vazorg [7]

Mass of X₂O₇ = 54,9g

2x + 33,6g = 54,9g
2x = 54,9g - 33,6g
2x = 21,3g | :2
x = 10,65g/mol

7 0

2 years ago

Read 2 more answers