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Natasha_Volkova [10]
3 years ago
11

If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potent

ial difference between the anode and cathode of this tube is 100.0 kV, how much power is expended
Physics
1 answer:
Zina [86]3 years ago
3 0

Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

N= 1.8*10^16 electrons

B. Power= I x v

= 30*10^-3A x 100*10^3v

= 3000watts

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