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4 years ago

{Help!} How does size impact the gravitational force??

2 answers:

5 0

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.

nikklg [1K]4 years ago

4 0

Hi,

your response would be

Faith

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The total resistance of a 15-ohm, an 65-ohm and a 35-ohm resistor connected in parallel

yanalaym [24]

Answer:

I think its 9.0397 Ohms

Explanation:

take the reciprocal of all the resistances: 1/15, 1/65, 1/35

then add them: = 151/1365

then reciprocal the answer: =1365/151

And chuck it on a calculator: =9.04 Ohms

I think this is right but I'm not entirely sure. Tell me if I'm right by the way!

3 0

3 years ago

A car has a mass of 2,500 kg. The car is accelerating at 0.5 m/s2. What is the net force acting on the car?

tekilochka [14]

Answer:

force:mass*acceleration

2500kg*0.5m/s2

1250N

6 0

3 years ago

What creates linear and rotary motion

Phantasy [73]

Answer:

A slider Crank Mechanism creates linear and rotary motion

Explanation:

7 0

4 years ago

How does the size of earth compare to jupiter

meriva

Size of Earth is small than the size of Jupiter.

5 0

3 years ago

Read 2 more answers

Water leaks out of a 3,200-gallon storage tank (initially full) at the rate V '(t) = 80 -t, where t is measured in hours and V i

kvasek [131]

Answer:

water leak is 650 gallons

time required to full drain is 80 hrs

Explanation:

given data

volume V = 3200 gallon

rate = V(t) = 80 - t

to find out

how much water leak between 10 and 20 hour and drain complete

solution

we know here rate is 80 - t

so here rate will be

$\frac{dV(t)}{dt}$ = 80 - t

and for time 10 and 20 hour

take integrate between 10 and 20

so water leak = $\int\limits^ {20}_ {10} {(80-t)} \, dt$ .....................1

water leak = ( 80t - $\frac{t^{2} }{2} )^{20}_{10}$

water leak = 650

so water leak is 650 gallons

and

we know here for full tank drain condition

water leak full = 80 t - $\frac{t^{2} }{2}$

3200 = 80 t - $\frac{t^{2} }{2}$

6400 = t² - 160 t

t = 80

so time required to full drain is 80 hrs

6 0

4 years ago