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andrew-mc [135]
3 years ago
9

Kristin has 3 2/3 yards of plaid ribbon. She has 2 5/6 yards of polka - dot ribbon. Estimate how many yards of ribbon Kristin ha

s in all. Explain how you know your estimate is reasonable.
Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

Step-by-step explanation:

Kristin has 3 2/3 yards of plaid ribbon. Converting 3 2/3 yards to improper fraction, it becomes 11/3 yards of plaid ribbon.

She has 2 5/6 yards of polka - dot ribbon. Converting 2 5/6 yards to improper fraction, it becomes 17/6 yards of polka - dot ribbon.

The total number of yards of ribbon that Kristin has would be

11/3 + 17/6 = (22 + 17)/6 = 39/6 yards of ribbon.

Converting to decimal, it becomes 6.5 yards of ribbon. Approximating 6.5 to the nearest yards, it becomes 7 yards. This is because the first digit after the decimal point is 5 and thus, can be rounded up

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Step-by-step explanation:


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Write an expression for the sequence of operations described below.
Murrr4er [49]

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<em>8</em><em>+</em><em>s</em><em>+</em><em>n</em>

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2 years ago
Toni bought 5 t-shirts for 35 if each T-shirt cost the same amount .how much tony would pay for20 shirts 
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8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \
Kisachek [45]

Answer:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2

Step-by-step explanation:

\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2}  t^2+1 \ \text{dt} = \ ?

We can use Part I of the Fundamental Theorem of Calculus:

  • \displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

  • \displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

  • \displaystyle\int\limits^b_a \text{f(t) dt}\  = -\int\limits^a_b \text{f(t) dt}

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

  • \displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx}  \int\limits^{x^2}_0 t^2+1 \text{ dt}  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

  • \displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]
  • where u represents any function other than a variable

For the first term, replace \text{t} with 2x, and apply the chain rule to the function. Do the same for the second term; replace

  • \displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)  

Simplify the expression by distributing 2 and 2x inside their respective parentheses.

  • [-(8x^2 +2)] + (2x^5 + 2x)
  • -8x^2 -2 + 2x^5 + 2x

Rearrange the terms to be in order from the highest degree to the lowest degree.

  • \displaystyle2x^5-8x^2+2x-2

This is the derivative of the given integral, and thus the solution to the problem.

6 0
2 years ago
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