A sample of liquid benzene at 80°C and a sample of gaseous benzene at 80°C will have the same average kinetic energy of benzene molecules.
Let us recall that the average kinetic energy of molecules depends on the molar mass of the substance as well as the temperature of the substance. We have that;
average kinetic energy=
R = gas constant
NA =Number of molecules
M = Temperature in Kelvin
We can see that the average kinetic energy depends on temperature therefore, a sample of liquid benzene at 80°C and a sample of gaseous benzene at 80°C will have the same average kinetic energy of benzene molecules.
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Ok so this is what we know :
2KClO3 -> 2KCl + 3O2 (Always check if equation is balanced - in this case it is)
4.26moles
So we know that we have 4.26 moles of oxygen (O2). Now lets look at the ratio between KClO3 and O2.
We see that the ratio is 2:3 meaning that we need 2KClO3 in order to produce 3O2.
Therefore divide 4.26 by 3 and then multiply by 2.
4.26/3 = 1.42
1.42 * 2 = 2.84
Now we know that the molarity of KClO3 is 2.84 moles.
Multiply by R.M.M to find how many grams of KClO3 we have.
R.M.M of KClO3
K- 39
Cl- 35.5
3O- 3 * 16 -> 48
---------------------------
<span>122.5
</span>2.84 * 122.5 = 347.9 grams therefore the answer is (a)
348 grams needed of KClO3 to produce 4.26 moles of O2.
Hope this helps :).
Explanation:
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the force of attraction of iron fillings towards magnet