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murzikaleks [220]
3 years ago
14

The periodic table... old help me is a test..​

Chemistry
1 answer:
Tom [10]3 years ago
5 0
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Which of the following is evidence of a chemical change?
krek1111 [17]
<span>the formation of a gas
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3 years ago
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For the reaction: 2H2O2 --&gt; 2H2 + 2O2, what is the total number of moles of O2 produced from the complete decomposition of 8
Softa [21]
2 H₂O₂ --> 2 H₂ + 2 O₂

2 moles H₂O₂ ------> 2 moles O₂
8 moles H₂O₂ ------> ?

moles O₂ = 8 x 2 / 2

moles O₂ = 16 / 2

= 8 moles

Answer C

hope this helps!
4 0
3 years ago
The compound responsible for the characteristic smell of garlic is allicin, c6h10os2. the mass of 1.00 mol of allicin, rounded t
Gemiola [76]

The compound responsible for the characteristic smell of garlic is allicin, that is having molecular formula C₆H₁₀OS₂.

Molar mass of C₆H₁₀OS₂=162.26 g mol⁻¹.

number of moles of C₆H₁₀OS₂=1 mol

So mass of C₆H₁₀OS₂ can be calculated as:


Number of moles of C_{6}H_{10}OS_{2}, n= \frac{Given mass of the }{Molar mass of theC_{6}H_{10}OS_{2}}

1= \frac{Given mass of the C_{6}H_{10}OS_{2}}{162.26}

Given mass of the C₆H₁₀OS₂= 162 g


4 0
3 years ago
An object which allows light to show through it unaltered is called?​
Rainbow [258]
Transparency (also called pellucidity or diaphaneity) in the field of optics is the physical property of allowing light to pass through the material without significant light dispersion.
6 0
3 years ago
How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you
SOVA2 [1]

Explanation:

The given data is as follows.

        Concentration of solution = 0.5 M

        Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically,      Molarity = \frac{\text{No. of moles}}{\text{Volume}}

Hence, calculate the number of moles as follows.

            No. of moles = Molarity × Volume

                                  = 0.5 M \times 1 L

                                  = 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

                                                      = 0.5 mol \times 132.119 g/mol

                                                      = 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.

8 0
3 years ago
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