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murzikaleks [220]
3 years ago
14

The periodic table... old help me is a test..​

Chemistry
1 answer:
Tom [10]3 years ago
5 0
Need more information
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F1
ololo11 [35]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Atomic Structure.

Since, We all know that, To draw any Electron-Dot Structure, we always have to know the exact Number of valence or free electrons of any atom or molecule, hence

The Correct Answer is :-

D. Number of valence electrons.

7 0
3 years ago
Balance the equation The synthesis of carborundum for sandpaper. _____ SiO2 + _____ C → _____ SiC + _____ CO
UkoKoshka [18]

Answer:

balanced chemical equation is

2 SiO₂ + 3 C₂ = 2 SiC + 4 CO

3 0
3 years ago
A 0.300 g piece of copper is heated and fashioned into a bracelet. The amount of energy transferred by heat to the copper is 66,
Alja [10]

Answer:

X=600 degrees celsius

Explanation:

We can evaluate by using the equation ==> Q=m(c)(delta T)

-We know the mass is 0.3 g

-Q= 66,300 J

-C= 390 j/g 0C

-Therefore, we need to solve for delta T (which will be represented by x)

 Q= mct

66,300 J= 0.3 g (390 J/g 0C) (t)

The unit of measurement (g-grams) can be crossed out on the left side of our expression.

66,300 J=0.3(390 J 0C) (t)

-If we convert into a proportional relationship:

66,300 J                117 J/0C x

------------       =        -----------

117 J/0C                 117 J/0C

-Joules on both sides can be crossed off

*117 J/0C came from the product in terms of 0.3(390 J 0C)

*If we find the quotient of 66,300 J and 117 J/0C, we get 566.6 repeating

-You may keep the answer as it is, although for simplicity reasons, we can round to the nearest hundred.

-Therefore, x=600.

-----Remember, x represented the delta t in our equation. (I made notice of that when evaluating).

Hope this helps! :)

3 0
3 years ago
Calculate the ph of 0.375 l of a 0.18 m acetic acid-0.29 m sodium acetate buffer after the addition of 0.0090 mol of koh. assume
Iteru [2.4K]

To calculate the pH of this solution, we use the Henderson-Hasselbalch equation: 

pH = pKa + log ([A-]/[HA])

Where,

[A-] = Molarity of the conjugate base = CH3COO- = 0.29 M<span>
<span>[HA] = Molarity of the weak acid  = CH3COOH = 0.18 M</span></span>

pKa = dissociation constant of the weak acid = 4.75

When KOH is added to the buffer, the chemical reaction is:

CH3COOH + KOH = CH3COO-K+ + H2O

Therefore when 0.0090 mol KOH is added, 0.0090 mol acid is neutralized, and 0.0090 mol CH3COO- is produced.

[CH3COO-] = [0.0090 mol + 0.375 L (0.29 mol/L) ] / 0.375 L = 0.314 M

[CH3COOH] = [-0.0090 mol + 0.375 L (0.18 mol/L) ] / 0.375 L = 0.156 M

Going back to Henderson-Hasselbalch equation:

pH = 4.75 + log (0.314 / 0.156)

<span>pH = 5.054</span>

7 0
3 years ago
Read 2 more answers
PLEAS HELP I HAVE LIMITED TIME!!
Burka [1]

Answer:

H2 is the limiting reactant.

Explanation:

From the diagram above:

H2 => White ball

O2 => Red ball

Before the reaction

H2 => White ball => 10

O2 => Red ball => 7

After the reaction

H2O => White and red ball => 10

O2 => 2

From the simple illustration above, we can see that all the H2 were used up in the reaction but there are left over of O2.

This simply means that H2 is the limiting reactant as all of it is used up in the reaction while O2 is the excess reactant as there are leftover.

7 0
3 years ago
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