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3 years ago

How do randomly moving molecules cause pressure to be exerted on a surface?

1 answer:

3 0

Imagine a crowd of people al jumping around in a room blindfolded. they will bump into each other and the walls. molecules behave the same way as a result of their temperature. the hotter the temperature, the more jumping and the greater the 'pressure' on the walls.

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Describe the mirror formula for a concave mirror in a shortcut way

sattari [20]

Answer:

1/f =1/v+1/u

Explanation:

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3 years ago

A horizontal line on a velocity/time graph shows ____ acceleration.

Novay_Z [31]

Answer:

Zero (0)

Explanation:

A horizontal line will be no movement of negative of positive acceleration

6 0

3 years ago

Read 2 more answers

A material having an index of refraction of 1.35 is used as an antireflective coating on a piece of glass (n = 1.50). What shoul

exis [7]

Answer:

103.70 nm

Explanation:

The minimum thickness of the film is given by $t=\frac{\lambda }{4n}$ where $\lambda$ is the wavelength and n is the index of the refraction

We have n =1.35

Wavelength $\lambda =560nm$

So the minimum thickness of the film $t=\frac{\lambda }{4n}=\frac{560}{4\times 1.35}=103.70\ nm$

3 0

3 years ago

100 g of Ice at -10°C is added into a

Andrei [34K]

Answer:

The mass of the juice responsible for melting the ice is 949.043 grams.

Explanation:

By the First Law of Thermodynamics, we understand that juice releases heat to the ice, which turns into water under the assumption that interactions between the ice-juice system and surroundings are negligible and energy processes are done in steady-state. Since juice is done with water, its specific heat will be taken as of the water. The process is described by the following formula:

$m_{i} \cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})] + m_{w} \cdot c_{w}\cdot (T_{4}-T_{3}) = 0$ (1)

Where:

$m_{i}$ - Mass of ice, in grams.

$m_{w}$ - Mass of the juice, in grams.

$c_{i}$ - Specific heat of ice, in joules per gram-degree Celsius.

$c_{w}$ - Specific heat of water, in joules per gram-degree Celsius.

$L_{f}$ - Latent heat of fusion, in joules per gram.

$T_{1}$ - Initial temperature of ice, in degrees Celsius.

$T_{2}$ - Melting point of water, in degrees Celsius.

$T_{3}$ - Final temperature of the ice-juice system, in degrees Celsius.

$T_{4}$ - Initial temperature of the juice, in degrees Celsius.

If we know that $m_{i} = 100\,g$ , $c_{i} = 2.090\,\frac{J}{g\cdot ^{\circ}C}$ , $c_{w} = 4.18\,\frac{J}{g\cdot ^{\circ}C}$ , $L_{f} = 334\,\frac{J}{g}$ , $T_{1} = -10\,^{\circ}C$ , $T_{2} = 0\,^{\circ}C$ , $T_{3} = 10\,^{\circ}C$ and $T_{4} = 20\,^{\circ}C$ , then the mass of the juice is:

$m_{w} = \frac{m_{i}\cdot [c_{i}\cdot (T_{1}-T_{2}) - L_{f} + c_{w}\cdot (T_{2}-T_{3})]}{c_{w} \cdot (T_{3}-T_{4})}$

$m_{w} = \frac{(100\,g)\cdot \left[\left(2.090\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C) - 334\,\frac{J}{g} +\left(4.18\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C) \right]}{\left(4.180\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (-10\,^{\circ}C)}$

$m_{w} = 949.043\,g$

The mass of the juice responsible for melting the ice is 949.043 grams.

5 0

3 years ago

How does Newton's third law of motion describe forces?

svetlana [45]

I would say your answer is B, since Newton's 3rd law is, "For every action, there is an equal and opposite reaction."
It's talking about pairs of actions. Sorry if I'm wrong.

3 0

3 years ago