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zhannawk [14.2K]
3 years ago
10

A horizontal line on a velocity/time graph shows ____ acceleration.

Physics
2 answers:
Novay_Z [31]3 years ago
6 0

Answer:

Zero (0)

Explanation:

A horizontal line will be no movement of negative of positive acceleration

dusya [7]3 years ago
3 0

Answer:

Zero acceleration

Explanation:

In a velocity-time graph, the gradient of the line describes how the acceleration varies.When the gradient is positive, it means we have a line that is upward sloping thus the accelaration is positive.When we have a negative gradient, it means the line is downward sloping thus the accelaration is negative.When the gradient is zero, there is no slope, thus the accelaration is zero, the case of a horizontal line.

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The position-time graph for a bug crawling along a line is shown in item 4 below. Determine whether the velocity is positive, ne
Naddika [18.5K]

Answer: The velocity at different marked time points are given as

t1 = -

t2 = +

t3 = +

t4 = -

t5 = 0

Explanation:

The slope of the tangent of the curve indicates the instantaneous velocity. So if the slope of the tangent is positive, that Is, the tangent makes a positive angle (above the horizontal axis) with the horizontal

axis, then the velocity at this point is positive, and if the slope of the tangent is negative, that is the tangent makes a negative angle with the horizontal axis (below the horizontal axis), then the velocity at this point is negative.

When the tangent of the line is parallel to the horizontal axis, the velocity is 0.

From the position-time graph attached, the sign on the instantaneous velocity for each time marked on the graph is given below

t1 = -

t2 = +

t3 = +

t4 = -

t5 = 0

QED!

5 0
3 years ago
Which of the following is the number of cycles per unit of time? infrasonis wave,frequency,ultrasonic wave or pitch
Allushta [10]
Frequency
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4 0
3 years ago
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A boy pushes forward a cart of groceries with a total mass of 40.0 kg. What is the acceleration of the cart if the net force on
melisa1 [442]

1.5m/s2

F=ma

a=F/m

a=60/40

a=1.5m/s2

6 0
3 years ago
A car moving in a straight line starts at X=0 at t=0. It passesthe point x=25.0 m with a speed of 11.0 m/s at t=3.0 s. It passes
Agata [3.3K]

Answer:

Average velocity v = 21.18 m/s

Average acceleration a = 2 m/s^2

Explanation:

Average speed equals the total distance travelled divided by the total time taken.

Average speed v = ∆x/∆t = (x2-x1)/(t2-t1)

Average acceleration equals the change in velocity divided by change in time.

Average acceleration a = ∆v/∆t = (v2-v1)/(t2-t1)

Where;

v1 and v2 are velocities at time t1 and t2 respectively.

And x1 and x2 are positions at time t1 and t2 respectively.

Given;

t1 = 3.0s

t2 = 20.0s

v1 = 11 m/s

v2 = 45 m/s

x1 = 25 m

x2 = 385 m

Substituting the values;

Average speed v = ∆x/∆t = (x2-x1)/(t2-t1)

v = (385-25)/(20-3)

v = 21.18 m/s

Average acceleration a = ∆v/∆t = (v2-v1)/(t2-t1)

a = (45-11)/(20-3)

a = 2 m/s^2

8 0
3 years ago
Why are all bodies in nature electrically neutral? short answer please​
DENIUS [597]

Answer: because they have equal numbers of protons

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3 0
2 years ago
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