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4 years ago

16 points and brainiest whoever is right

Physics

1 answer:

masha68 [24]4 years ago

6 0

Let k be the spring constant. Then you have
188=k*21.8
k=188/21.8=8.62,
In the second part you use
m g= k x
x=m g/k= 38/8.62=4.4cm

4.4 cm is the answer

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Three metal fishing weights, each with a mass of 1.00x102 g and at a temperature of 100.0°C, are placed in 1.00x102 g of water a

worty [1.4K]

Answer:

Approximately $0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}}$ assuming no heat exchange between the mixture and the surroundings.

Explanation:

Consider an object of specific heat capacity $c$ and mass $m$ . Increasing the temperature of this object by $\Delta T$ would require $Q = c\, m \, \Delta T$ .

Look up the specific heat of water: $c(\text{water}) = 4.182\; {\rm J \cdot g^{-1} \cdot K^{-1}}$ .

It is given that the mass of the water in this mixture is $m(\text{water}) = 1.00 \times 10^{2}\; {\rm g}$ .

Temperature change of the water: $\Delta T(\text{water}) = (45 - 35)\; {\rm K} = 10\; {\rm K}$ .

Thus, the water in this mixture would have absorbed :

$\begin{aligned}Q &= c\, m\, \Delta T \\ &= 4.182\; {\rm J \cdot g^{-1}\cdot K^{-1}} \\ &\quad \times 1.00 \times 10^{2}\; {\rm g} \times 10\; {\rm K} \\ &= 4.182 \times 10^{3}\; {\rm J}\end{aligned}$ .

Thus, the energy that water absorbed was: $Q(\text{water}) = 4.182 \times 10^{3}\; {\rm J}$ .

Assuming that there was no heat exchange between the mixture and its surroundings. The energy that the water in this mixture absorbed, $Q(\text{water})$ , would be the opposite of the energy that the metal in this mixture released.

Thus: $Q(\text{metal}) = -Q(\text{water}) = -4.182 \times 10^{3}\; {\rm J}$ (negative because the metal in this mixture released energy rather than absorbing energy.)

Mass of the metal in this mixture: $m(\text{metal}) = 3 \times 1.00 \times 10^{2}\; {\rm g} = 3.00 \times 10^{2}\; {\rm g}$ .

Temperature change of the metal in this mixture: $\Delta T(\text{metal}) = (100 - 45)\; {\rm K} = 55\; {\rm K}$ .

Rearrange the equation $Q = c\, m \, \Delta T$ to obtain an expression for the specific heat capacity: $c = Q / (m\, \Delta T)$ . The (average) specific heat capacity of the metal pieces in this mixture would be:

$\begin{aligned}c &= \frac{Q}{m\, \Delta T} \\ &= \frac{-4.182 \times 10^{3}\; {\rm J}}{3.00 \times 10^{2}\; {\rm g} \times (-55\; {\rm K})} \\ &\approx 0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}}\end{aligned}$ .

6 0

3 years ago

Two things that electrical force depends upon?

lidiya [134]

Electric force depends on the charge and the strength of the electric field. The equation that relates the three:

F = Eq where q is the charge and E is the electric field strength.

4 0

3 years ago

The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°c _____.

Fiesta28 [93]

Answer:

4.2 J

Explanation:

Specific heat capacity: This is defined as the amount of a heat required to rise a unit mass of a substance through a temperature of 1 K

From specific heat capacity,

Q = cmΔt.............................. Equation 1

Where Q = amount of energy absorbed or lost, c = specific heat capacity of water, m = mass of water, Δt = Temperature rise.

Given: m = 1 g = 0.001 kg, Δt = 1 °C

Constant : c = 4200 J/kg.°C

Substitute into equation 1

Q = 0.001×4200(1)

Q = 4.2 J.

Hence the energy absorbed or lost = 4.2 J

6 0

4 years ago

Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r

Zepler [3.9K]

Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example

answer : a) 14 ohms b) 0.86 amps c) 10.32 V

Explanation:

Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms

Voltage source = 12V

Assuming that the Resistors are in series 

a) Determine Total resistance

Req = R1 + R2 + R3

= 3 + 4 + 5 = 14 ohms

b) Total current

Ieq = V / Req

= 12 / 14 = 0.86 amps

c) The Total Voltage over the entire system

Vt = ∑ Voltage drops

= ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )

= 10.32 V

5 0

3 years ago

A transformer consists of 340. primary windings and 980. secondary windings. If the emf of the primary coil is 30.0 V, what is t

xxTIMURxx [149]

Answer:

86.47 V

Explanation:

It will be multiplied by the ratio of the windings

980/340 * 30 = 86.47 v

4 0

2 years ago