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3 years ago

What would be the effects of a baseball strike

Physics

1 answer:

Ipatiy [6.2K]3 years ago

4 0

Answer:

If you get 3 strikes in baseball your out and your batting Turn is Over

Explanation:

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Father drove 176 km in 7 hours. For the first 92 km, he spent

Verizon [17]

Answer:

28km/h

Explanation:

92km = 4 hours

176 - 92 = 84

84km = 3 hours

84/3 = 28

28km/h

Hopefully this helps you :)

pls mark brainlest ;)

3 0

3 years ago

Water flows through a water hose at a rate of Q1 = 860 cm3/s, the diameter of the hose is d1 = 1.85 cm. A nozzle is attached to

Snowcat [4.5K]

Answer:

a) A1 = $\frac{\pi (d1)^{2} }{4}$

b) A1 = 2.688 cm $^{2}$

c) Q1 = A1 x v1

d) v1 = 3.1994 m/s

e) A2 = $\frac{A1 X v1}{v2}$

f) A2 = 0.7963cm $^{2}$

Explanation:

a) Area = $\pi r^{2}$

r = $\frac{d}{2}$

thus,

area = $\pi (\frac{d}{2})^{2}$

A1 = $\frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 = [tex]\frac{\pi (d1)^{2} }{4}$

A1 = $\frac{\pi (1.85)^{2} }{4}$

A1 = 2.688 cm $^{2}$

c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)

Q1 = A1 x v1

d) From the above equation,

v1 = $\frac{Q1}{A1}$ = $\frac{860}{2.688}$ = 319.94 cm/s = 3.1994 m/s

e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.

i.e. A1 x v1 = A2 x v2

thus,

A2 = $\frac{A1 X v1}{v2}$

f) v2 = 10.8 m/s.

substituting the values in the above equation,

A2 = $\frac{2.688 X 3.1994}{10.8}$ = 0.7963cm $^{2}$

3 0

4 years ago

The following position vs time graph shows the motion of an object along its path from -10 to seconds. Based on this graph, what

Marrrta [24]

∆x (displacement) = v - u

where, v is the final position and u is the initial position.

Given, the final position of the object is 0 m and the initial position is 5 m.

∆x (displacement) = v - u

= 0 m - 5 m

= -5 m

Therefore, <u>C: -5m</u> is the correct answer.

6 0

3 years ago

A 4.1-kg ball is thrown from the top of a 4-m tall building (point A) with a speed of 1 m/s at an angle 2 degrees above the hori

lubasha [3.4K]

Answer:

$K.E = 163 J$

Explanation:

From the question we are told that:

Mass $m=4.1kg$

Height $h=4m$

Speed $V=1m/s$

Angle $\theta= 2 \textdegree$

Generally the equation for K.E is mathematically given by

Since

The potential energy and kinetic energy is equal to the kinetic energy as it hits the ground.

Therefore

$K.E=mgH + 0.5mV^2$

$K.E = (4.1)(9.81)(4) + (4.1)(1)^2*0.5$

$K.E = 163 J$

6 0

3 years ago

I want to improve my target shooting accuracy by 20 percent what change would make this statement a more powerful goal?

prohojiy [21]

I think the correct answer from the choices listed above is option C. The change in the statement that would make a more powerful goal would be to make <span>it measurable by explaining how far away the target is. Hope this answers the question. Have a nice day.</span>

7 0

3 years ago

Read 2 more answers