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Arte-miy333 [17]
4 years ago
10

In ΔABC shown below, ∠BAC is congruent to ∠BCA:

Mathematics
1 answer:
Anettt [7]4 years ago
3 0
<span>Construct a perpendicular bisector from point B to Line segment AC.
Label the point of intersection between this perpendicular bisector and Line segment AC as point D:

m∠BDA and m∠BDC is 90° by the definition of a perpendicular bisector.

∠BDA is congruent to ∠BDC by the definition of congruent angles.

Line segment AD is congruent to Line segment DC by </span><span> the definition of a perpendicular bisector</span><span>.

ΔBAD is congruent to ΔBCD by the </span><span>Angle-Side-Angle (ASA) Postulate</span><span>.

Line segment AB is congruent to Line segment BC because corresponding parts of congruent triangles are congruent (CPCTC).

Consequently, ΔABC is isosceles by definition of an isosceles triangle.</span>

Therefore, the correct answer is C.
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