The temperature of a system rises by 45°C during a heating process. Express this rise in temperature in Kelvin. (Round the final
1 answer:
You might be interested in
<u>Answer:</u> The potential of the given cell is 1.551 V
<u>Explanation:</u>
The given chemical cell follows:
<u>Oxidation half reaction:</u>
<u>Reduction half reaction:</u> ( × 2)
<u>Net cell reaction:</u>
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate the EMF of the cell, we use the Nernst equation, which is:
where,
= electrode potential of the cell = ? V
= standard electrode potential of the cell = +1.561 V
n = number of electrons exchanged = 2
Putting values in above equation, we get:
Hence, the potential of the given cell is 1.551 V