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Aleks [24]
3 years ago
14

Most scientific questions are based on opinions. hypotheses. observations. experimental dat

Chemistry
1 answer:
lapo4ka [179]3 years ago
5 0
Most scientific questions are based on observations. Scientists observe something repeatedly, and they do the experiments over and over again, so as to get to the bottom of some of their questions. 
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Which statement describes the phase change that occurs when dry ice is placed in an open container at room temperature?
zloy xaker [14]

Answer:

Dry ice undergoes sublimation, an endothermic change at room temperature.

7 0
3 years ago
Read 2 more answers
450g of chromium(iii) sulfate reacts with excess potassium phosphate. How many grams of potassium sulfate will be produced? (ANS
Irina18 [472]

Answer:

600 g K₂SO₄

Explanation:

First write down the complete, balanced chemical equation for such question. In this case:

Cr₂(SO₄)₃ + 2K₃PO₄ →  3K₂SO₄ + 2CrPO₄

Next, calculate molar masses of required compounds mentioned in the question. In this case it is for Cr₂(SO₄)₃ and K₂SO₄.

  • Molar mass(MM) of Cr₂(SO₄)₃:

        = 2*(MM of Cr) + 3*( MM of S) + 3*4*( MM of O)

        = 2*(52) + 3*(32) + 12*(16)

        = 104 + 96 + 192

        = 392 g

  • Molar mass(MM) of K₂SO₄:

        = 2*(MM of K) + 1*( MM of S) + 4*( MM of O)

        = 2*(39) + 32 + 4*(16)

        = 78 + 32 + 64

        = 174 g

Here comes the concept of Limiting reagent:

The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it. The other reactants present with this are usually in excess and called excess reactants. If quantities of both the reactants are given, then one should apply unitary method and find out the limiting reagent out of the two. Then, determine the amount of product formed or percentage yield.

Also, 1 mole( 392 g) of Cr₂(SO₄)₃ gives 3 moles( 174*3 = 522 g) of K₂SO₄.

Using unitary method, if 392g of Cr₂(SO₄)₃ gives 522 g of K₂SO₄ , then 450 g of Cr₂(SO₄)₃ will give how much of K₂SO₄?

Yeild of K₂SO₄ : \frac{522 * 450}{392}

That is 599.3 g.

Since we have not considered molecular masses of individual atoms to 6 decimal places, this number can be approximated to 600g.

Therefore, 600g of K₂SO₄ is produced.

6 0
3 years ago
Neptunium-237 was the first isotope of a transuranium element to be discovered. the decay constant is /s. what is the half-life
kari74 [83]

The half-life in years of Neptunium-237 which was the first isotope is 2.1 10^{6} years.

Neptunium is most stable and Neptunium-237 is undergoes alpha decay, it means Neptunium-237 is decays by the emission of alpha particles . Seven alpha particles is emitted during decay of  Neptunium-237.  Neptunium-237 is radioactive actinide  elements and first  transuranium element.

The transuranium synthesis process involves creating a transuranium element through the transmutation process . The transmutation process  is the process of creating heavy elements from light elements. Hence the process is the transmutation of light elements. There are two types: artificial and natural transmutation.

to learn more about transuranium element.

brainly.com/question/1491386

#SPJ4

6 0
2 years ago
when writing numbers using scientific notation, numbers greater than one have..... exponents and numbers less than one have.....
Sav [38]
Positive and negative
8 0
3 years ago
A 2.5 L container holds a sample of hydrogen gas at 291 K and 180 kPa.
netineya [11]

Answer:

The new temperature will be 565.83 K.

Explanation:

Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.

In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

\frac{P}{T} =k

When an ideal gas goes from a state 1 to a state 2, it is true:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 180 kPa
  • T1= 291 K
  • P2= 350 kPa
  • T2= ?

Replacing:

\frac{180 kPa}{291 K} =\frac{350 kPa}{T2}

Solving:

T2=350 kPa*\frac{291 K}{180 kPa}

T2= 565.83 K

<u><em>The new temperature will be 565.83 K.</em></u>

6 0
3 years ago
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