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Aleks [24]
3 years ago
14

Most scientific questions are based on opinions. hypotheses. observations. experimental dat

Chemistry
1 answer:
lapo4ka [179]3 years ago
5 0
Most scientific questions are based on observations. Scientists observe something repeatedly, and they do the experiments over and over again, so as to get to the bottom of some of their questions. 
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Someone help me out with these chemistry (stoichiometry)
lana66690 [7]

Answer:Videos

For example, when oxygen and hydrogen react to produce water, one mole of oxygen ... These conversion factors state the ratio of reactants that react but do not tell ... In a typical chemical equation, an arrow separates the reactants on the left ... For example, to determine the number of mol

6 0
3 years ago
The density of a material is a/an ___________.
Nitella [24]

The density of a material is an intensive property.

<h3>What is intensive property?</h3>

An intensive property of matter is one that does not change with the amount of matter. It is a bulk property, which means that it is a physical property that is independent of sample size or mass. An extensive property, on the other hand, is one that is affected by sample size.

<h3>What factors influence an intensive property?</h3>

Intensive properties are those that are determined solely by the characteristics of the material and not by its quantity - for example, density, temperature, refractive index, color, and pressure. Intensive properties are not additive, which means their value does not change when the amount of material is changed.

Learn more about the intensive property here:-

brainly.com/question/24909279

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5 0
1 year ago
Which of the following is a change of state?
Step2247 [10]

Answer:

I think C. Hope this Helps!

Explanation:

5 0
3 years ago
For the reaction C2H4(g) + H2O(g) --&gt; CH3CH2OH(g)
Dominik [7]

Answer : The value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = -45.6 kJ = -45600 J

\Delta S^o = standard entropy = -125.7 J/K

T = temperature of reaction = 262.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(-45600J)-(262.0K\times -125.7J/K)

\Delta G^o=-12666.6J=-12.7kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = -12666.6 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 262.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

-12666.6J=-(8.314J/K.mol)\times (262.0K)\times \ln k

k=3.35\times 10^{2}

Therefore, the value of equilibrium constant for this reaction at 262.0 K is 3.35\times 10^{2}

3 0
4 years ago
The half-life of tritium, or hydrogen-3, is 12.32 years. After about 37 years, how much of a sample of tritium will remain uncha
Pachacha [2.7K]
1/16 ( ignore this the stupid website just makes us use 20 characters UGH! )
7 0
3 years ago
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