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2 years ago

PLEASE HELP!! What is the concentration [H3O+] of a solution with a pH of 13.2? Is the solution acidic, basic, or neutral?

Chemistry

2 answers:

asambeis [7]2 years ago

8 0

$\\ \tt\leadsto pH=-log[H^+]$

$\\ \tt\leadsto -log[H^+]=13.2$

$\\ \tt\leadsto log[H^+]=-13.2$

$\\ \tt\leadsto [H^+]=antilog(-13.2)=6.3\times 10^{-14}M$

Ilya [14]2 years ago

3 0

The concentration of [H3O+] will be 6.3 x $10^{-14}$ M

Mathematically, pH = -log [H+] or -log [H3O+]

With a pH of 13.2:

-log [H3O+] = 13.2

log [H3O+] = -13.2

[H3O+] = 6.3 x $10^{-14}$ M

More on pH can be found here: brainly.com/question/491373

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3 years ago

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How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci

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Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

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Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

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I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

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4 years ago

. A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. Th

mafiozo [28]

Answer:

The concentration of CaCl2 in this solution is 0.564 molar (option A)

Explanation:

Step 1: Data given

Mass of CaCl2 = 23.7 grams

Mass of water = 375 grams

Density of solution is 1.05 g/mL

Step 2: Calculate total mass

Total mass = mass of CaCl2 + mass of water

Total mass = 23.7 grams + 375 grams = 398.7 grams

Step 3: Calculate volume of the solution

Density = mass / volume

Volume = mass / density

Volume = 398.7 grams / 1.05 g/mL

Volume = 379.7 mL = 0.3797 L

Step 4: Calculate moles CaCl2

Moles CaCl2 = mass CaCl2 / molar mass CaCl2

Moles CaCl2 = 23.7 grams / 110.98 g/mol

Moles CaCl2 = 0.214 moles

Step 5: Calculate concentration

Concentration of CaCl2 = moles / volume

Concentration of CaCl2 = 0.214 moles / 0.3797 L

Concentration of CaCl2 = 0.564 mol / L = 0.564 molar

The concentration of CaCl2 in this solution is 0.564 molar (option A)

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