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1 year ago

PLEASE HELP!! What is the concentration [H3O+] of a solution with a pH of 13.2? Is the solution acidic, basic, or neutral?

Chemistry

2 answers:

asambeis [7]1 year ago

8 0

$\\ \tt\leadsto pH=-log[H^+]$

$\\ \tt\leadsto -log[H^+]=13.2$

$\\ \tt\leadsto log[H^+]=-13.2$

$\\ \tt\leadsto [H^+]=antilog(-13.2)=6.3\times 10^{-14}M$

Ilya [14]1 year ago

3 0

The concentration of [H3O+] will be 6.3 x $10^{-14}$ M

Mathematically, pH = -log [H+] or -log [H3O+]

With a pH of 13.2:

-log [H3O+] = 13.2

log [H3O+] = -13.2

[H3O+] = 6.3 x $10^{-14}$ M

More on pH can be found here: brainly.com/question/491373

#SPJ1

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How many grams of hcl can be produced from the reaction of 23 moles of h2 and 875g of cl2?

max2010maxim [7]

Answer: 899 g

Explanation:

Since the mass of a mole of diatomic chlorine is about 70.9 g/mol, this means that 875 grams is about 875/70.9 = 12.3 mol.

Hence, we know that chlorine is the limiting reactant, and that about 12.3 moles of chlorine will be consumed.

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2 years ago

A chemical reaction was used to produce 2.95 moles of copper(II) bicarbonate, Cu(HCO3)2.

BARSIC [14]

Answer:

About 547 grams.

Explanation:

We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.

To do so, we can use the initial value and convert it to grams using the molar mass.

Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

$\displaystyle \begin{aligned} \text{MM}_\text{Cu(HCO$_3$)$_2$} &= (63.55 + 2(1.01)+2(12.01)+6(16.00))\text{ g/mol} \\ \\ &=185.59\text{ g/mol} \end{aligned}$

Dimensional Analysis:

$\displaystyle 2.95\text{ mol Cu(HCO$_3$)$_2$}\cdot \frac{185.59 \text{ g Cu(HCO$_3$)$_2$}}{1 \text{ mol Cu(HCO$_3$)$_2$}} \Rightarrow 547 \text{ g Cu(HCO$_3$)$_2$ }$

In conclusion, about 547 grams of copper (II) bicarbonate is produced.

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3 years ago

SCIENCEEEE!!!!! HELPPPP!!!!

IRINA_888 [86]

pretty sure it's both are physical changes.

5 0

3 years ago

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gulaghasi [49]

Taking into account the change of units, the size of the tank is 54.88 liters.

In first place, the rule of three is a tool used to quickly solve problems involving a proportional relationship between two variables.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three should be applied.

The rule of three is applied as follows, with A, B and C being known values and D being an unknown value: if A maintains a certain relationship with B, and it is known that C and D have the same relationship, it is possible to calculate the unknown value D using the following expression:

$D=\frac{CxB}{A}$

In this case, the rule of three can be applied as follows: if 1 gallon is equal to 3.785 liters, 14.5 gallons are equal to how many liters?

$D=\frac{14.5 gallonsx3.785 liters}{1 gallon}$

Solving:

D= 54.88 liters

In summary, the size of the tank is 54.88 liters.

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