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serious [3.7K]
3 years ago
13

You are to create a story for a child of 5-6 years old. You will explain the brain and its functions to them. You need to use th

e following terms and explain their functions in simple terms. Use the format of a story to keep the child interested, and be sure to use illustrations. Add characters (Dora, Superman, etc.) to make the information fun.
Physics
1 answer:
ZanzabumX [31]3 years ago
4 0
First of all I can't write the story for you but I can help you brain Storm.
1. Choose the character you know the most about If you know Super Hero's,Cartoons etc. use what you know then it won't look like you're randomly throwing things in. 
2. Figure out witch part of the brain you want to talk about, the facts you want to put in there, and organize your facts.
3. Put it in little kid language, use small words and not BIG words 5-6 year old's have a good Vocabulary but it is better to use small words.
Ok hope you have fun writing this story!
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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o
Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m

The fundamental frequency of the wire is given by

f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N

The tension in the wire is 67.9064 N

7 0
3 years ago
An object moving north with an initial velocity of 14m/s accelerates 5m/s squared for 20 seconds. What is the final velocity of
Gemiola [76]

Since it moves 5 m/s faster every second, after 20 seconds it's moving 100 m/s faster than when it started speeding up.

If it was moving at 14 m/s when the acceleration began, it's moving at 114 m/s at the end of the 20 seconds.  Its velocity is <em>114 m/s North.</em>

That's 255 mph !

4 0
3 years ago
Star Twinkle but planet do not why​
V125BC [204]

Answer:The total variation in the amount of light entering our eye is not dectiable therefore planets do not twinkle.

Explanation:Stars twinkle, while planets (usually) shine steadily. Why? Stars twinkle because … they're so far away from Earth that, even through large telescopes, they appear only as pinpoints. ... Planets shine more steadily because … they're closer to Earth and so appear not as pinpoints, but as tiny disks in our sky.As light from a star races through our atmosphere, it bounces and bumps through the different layers, bending the light before you see it. Since the hot and cold layers of air keep moving, the bending of the light changes too, which causes the star's appearance to wobble or twinkle.

7 0
3 years ago
A 20.0-µF capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280
natali 33 [55]

Answer

given,

Capacitance of capacitor = 20.0-µF

Voltage =  150.0-V

inductance = 0.280 m H

a) the oscillation frequency of circuit

f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{LC}}

f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{0.280 \times 10^{-3}\times 20 \times 10^{-6}}}

f = 2126.9 Hz

b) U = \dfrac{1}{2}CV^2

   U = \dfrac{1}{2}(20\times 10^{-6})(150)^2

         U = 0.225 J

c)Current in the inductor

    V = L \dfrac{dI}{dt}

    150 = 0.28 \times 10^{-3} \dfrac{dI}{dt}

    \dfrac{dI}{dt} = 535714

instantaneous rate of change of current is equal to 535714 A/s

 

7 0
3 years ago
Which of the following would not increase the velocity of a sound wave in air? A. lowering the humidity of the air. B. increasin
Rashid [163]
A. Lowering the humidity of the air.

Hope this helps!
6 0
4 years ago
Read 2 more answers
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