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serious [3.7K]
3 years ago
13

You are to create a story for a child of 5-6 years old. You will explain the brain and its functions to them. You need to use th

e following terms and explain their functions in simple terms. Use the format of a story to keep the child interested, and be sure to use illustrations. Add characters (Dora, Superman, etc.) to make the information fun.
Physics
1 answer:
ZanzabumX [31]3 years ago
4 0
First of all I can't write the story for you but I can help you brain Storm.
1. Choose the character you know the most about If you know Super Hero's,Cartoons etc. use what you know then it won't look like you're randomly throwing things in. 
2. Figure out witch part of the brain you want to talk about, the facts you want to put in there, and organize your facts.
3. Put it in little kid language, use small words and not BIG words 5-6 year old's have a good Vocabulary but it is better to use small words.
Ok hope you have fun writing this story!
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A 0.74 mF capacitor is connected to a standard outlet (rms voltage 82 V, frequency 49 Hz ). Determine the magnitude of the curre
disa [49]

Answer:

I =  26.36 cosω t A

Explanation:

Given that

C=0.74 mF

Vrms= 82 V

Frequency ,f= 49 Hz

We know that ω = 2 π f

ω = 2 x  π x 49

ω = 307.72 rad/s

As we know that voltage given as

V= Vo sinω t

V_o=\sqrt2\ V_{rms}

V_o=\sqrt2\ \times 82\

Vo=115.96 V

V=115.96 sinω t

The current given as

I=C\dfrac{dV}{dt}

I=0.74\times \dfrac{dV}{dt}\ mA

\dfrac{dV}{dt}=115.96\omega cos\omega t

I=0.74\times 115.96\times 307.22 cos\omega t\ mA

I = 26362.67 cosω t mA

I =  26.36 cosω t A

This is the current at time ant time t.

7 0
3 years ago
The smallest possible part of an element that can still be identified as the element is called
andreyandreev [35.5K]

Answer:

BLM

Explanation:

ACAB

4 0
3 years ago
Vector c has a magnitude 24.6 m and is in the direction of the negative y-axis. vectors a and b are at angles α = 41.4° and β
storchak [24]
The vector c has a magnitude of 24.6m and it is in the negative y direction. Therefore
\vec{c} = - 24.6 \hat{j}

The vector b is 41.4° up from the x-axis. Therefore
\vec{b} = b[cos(41.4^{o}) \hat{i} + sin(41.4^{o}) \hat{j} ] =b(0.75\hat{i} + 0.6613 \hat{j})

The vector a is 27.7° up from the x-axis. Therefore
\vec{a} = a[cos(22.7^{o})\hat{i} + sin(27.7^{o})\hat{j}] =  a(0.8854\hat{i} + 0.4648\hat{j})

Because \vec{a} +\vec{b} + \vec{c} = 0, the sum of the x and y components should be zero. Therefore,
For the x-component,
0.8854a + 0.75b = 0
 or
 a + 0.847b = 0                            (1)
For the y-component,
0.4648a + 0.6613b - 24.6 = 0
 or
 a + 1.4228b = 52.926                (2)

Subtract (1) from (2).
0.5758b = 52.926
b = 91.917
a = -0.847b = -77.854

Answer:
The magnitude of vector a is -77.85 m
The magnitude of vector b is 91.92 m
5 0
3 years ago
PLEASE HURRY
Sophie [7]

Decompose the forces acting on the block into components that are parallel and perpendicular to the ramp. (See attached free body diagram. Forces are not drawn to scale)

• The net force in the parallel direction is

∑ <em>F</em> (para) = -<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>

• The net force in the perpendicular direction is

∑ <em>F</em> (perp) = <em>n</em> - <em>mg</em> cos(21°) = 0

Solving the second equation for <em>n</em> gives

<em>n</em> = <em>mg</em> cos(21°)

<em>n</em> = (0.200 kg) (9.80 m/s²) cos(21°)

<em>n</em> ≈ 1.83 N

Then the magnitude of friction is

<em>f</em> = <em>µn</em>

<em>f</em> = 0.25 (1.83 N)

<em>f</em> ≈ 0.457 N

Solve for the acceleration <em>a</em> :

-<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>

<em>a</em> = (-0.457N - (0.200 kg) (9.80 m/s²) sin(21°))/(0.200 kg)

<em>a</em> ≈ -5.80 m/s²

so the block is decelerating with magnitude

<em>a</em> = 5.80 m/s²

down the ramp.

5 0
3 years ago
As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 2.91 back-and-forth cy
Lapatulllka [165]

Answer:

Wavelength, \lambda=0.011\ m

Explanation:

Given that,

Number of cycles in a spiral spring is 2.91 in every 3.67 s

The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s

To find,

Wavelength

Solution,

Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,

f=\dfrac{2.91}{3.67}=0.79\ Hz

The wavelength of a wave is given by :

\lambda=\dfrac{v}{f}

\lambda=\dfrac{0.00925\ m/s}{0.79\ Hz}

\lambda=0.011\ m

So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.

8 0
3 years ago
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