Let's start by differentiating the terms distance and displacement. They both refer to the length of paths. Distance only accounts for the total length regardless of the path taken. Displacement measures the linear path from the starting point to the end point. So, it does not necessarily follow the actual path. However, for this problem, assuming that the path is just in one direction, displacement and distance would just be equal. The equation would be:
Distance = Displacement = v₀t + 0.5at² = 0(10 s) + 0.5(+1.2 m/s²)(10 s)²
Distance = Displacement = 60 meters
I think the answer for the question above its b 1.2
Answer:
1110 N
Explanation:
First, find the acceleration.
Given:
Δx = 300 m
v₀ = 85.5 km/h = 23.75 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (23.75 m/s)² + 2a (300 m)
a = -0.94 m/s²
Find the force:
F = ma
F = (1180 kg) (-0.94 m/s²)
F = -1110 N
The magnitude of the force is 1110 N.
Answer:
Explanation:
The rms voltage = 140/√2 = 140/1.414 = 99 V.
Reactance of inductor = wL = 2 X 3.14 X 100 X 113 X 10⁻³ =70.96 ohm.
Total resistance in terms of vector = 50+70.96j
j is imaginary unit number
Magnitude of this resistance = √ 50² + 70.96² = 86.80 ohm
current in resistance (rms) ( I ) = 99/86.80 = 1.14 A.
Power dissipated in resistor = I² R = 1.14 X 1.14 X 50 = 65 W( approx)
