I think it's false because Oxygen is diatomic so it's found as O2 which means that it has two atoms of itself.
Answer:
yes it was a constant speed and the car traveled 10 meters in 20 seconds.
Explanation:
Answer:
Despite being such prominent feature on our planet, much of the mid-ocean ridge system remains a mystery. While we have mapped about half of the global mid-ocean ridge in high resolution, less than one percent of the mid-ocean ridge has been explored in detail using submersibles or remotely operated vehicles. so therefore we do not have enough information about them to know what will happen
Explanation:
A mid-ocean ridge or mid-oceanic ridge is an underwater mountain range, formed by plate tectonics. This uplifting of the ocean floor occurs when convection currents rise in the mantle beneath the oceanic crust and create magma where two tectonic plates meet at a divergent boundary. Mid-ocean ridges occur along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart. As the plates separate, molten rock rises to the seafloor, producing enormous volcanic eruptions of basalt. The speed of spreading affects the shape of a ridge slower spreading rates result in steep, irregular topography while faster spreading rates produce much wider profiles and more gentle slopes.
Answer:
True
Explanation:
Atoms of the same element will always have the same atomic mass or the mass listed in the periodic table.
To solve this problem we will use the kinematic equations of descriptive motion of a projectile for which both the height reached and the distance traveled are defined. From this type of movement the lion reaches a height (H) of 3m and travels a horizontal distance (R) of 10 m. Mathematically the equations that describe this movement are given as,
Dividing the two equation we have that
Substituting values of H and R, we get
Substituting the value of \theta in equation we get,
Therefore the speed of the mountain lion just as it leaves the ground is 9.98m/s at an angle of 50.2°
