Answer:175.42m/s
Explanation:
Wavelength=0.49m
Frequency=358Hz
Velocity=frequency x wavelength
Velocity=358x0.49
Velocity=175.42m/s
Ultrasound is vibrations, just like sound is vibrations. Ultrasound travels though the body just like sound would and when it hits something, it bounces back, where it is picked up by a receiver. which then makes an image out of it.
X-rays are electromagnetic waves, like visible light. Other examples of electromagnetic waves are infrared, and ultraviolet. But people cant see infrared nor ultraviolet, even though they are just like visible light. The difference between visible light and all these other kinds of light are just like the difference between red and blue. They are both light but different colors, ultraviolet and infrared are colors we cannot see, and in fact, we can see only a tiny portion of the colors out there. X-rays are just like all these kinds of light and we cant see it but it is able to go through most of the body, bot not bone. Doctors use x-rays to see bones and things like that in the body because x-rays won't pass through bone, but they will go through muscle and skin. So when a doctor takes an x-ray, its just like making a silhouette, but with colors we cant see. Of course, the x-rays make the photo paper change color and that's how we are able to see the image but the principle is the same.
There are 7 planets in all
<span>The key equation is going to come from Mr Planck: E=h \nu
Where h is Plancks constant; and ν is the frequency. This equation gives you the energy per photon at a given frequency. Alas, you're given wavelength, but that's easy enough to convert to frequency given the following equation:
c= lambda / nu
where c is the speed of light; λ (lambda) is the wavelength; and ν is again frequency. As soon as you know the energy of a photon with a wavelength of 550nm, you should know how many photons you would require to accumulate 10^-18J. Be careful with your units.</span>
Answer:
Explanation:
it is a force generated in matter by the motion of electrons within its atoms.
