7.5 × 10¹⁴ Hz is the highest frequency of visible light when wavelengths of visible light range from 400 nm to 700 nm.
The distance a wave travels in one unit of time is known as the wave speed (v).Taking into account that the wave travels one wavelength in one interval,
v=λ/T
Given that T = 1/f, we can write the equation above as,
V = f λ
Given data:
Minimum wavelength of visible light = 400 nm = 4 × 10⁻⁷ m
Speed of light = 3 × 10⁸ m/s
Frequency = c/λ = 3 × 10⁸ / 4 × 10⁻⁷
= 7.5 × 10¹⁴ Hz
To learn more about Frequency: brainly.com/question/16200748
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False sometimes you get a bad mutation
Answer:
The answer of this question is =1.258*10-4
Data:

n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>

Wire 2 → 2º Harmonic → n = 2







Wire 1 → 1º Harmonic or Fundamental rope → n = 1



If, We have:
V = 42L
Soon:



Answer:
<span>The fundamental frequency of the string:
</span>
21 Hz
Answer:
2m head start or else you done for
Explanation:
you cant even out run a bear they run at 35mph the fastest human is 25